With 2 dices we have all 6x6=36 ways.
But for two conditions: sum 8 and both even numbers, we have only: (2;6), (6;2), (4;4). That's all.
And the probability is 3/36= 1/12
Have fun
Base case: if <em>n</em> = 1, then
1² - 1 = 0
which is even.
Induction hypothesis: assume the statement is true for <em>n</em> = <em>k</em>, namely that <em>k</em> ² - <em>k</em> is even. This means that <em>k</em> ² - <em>k</em> = 2<em>m</em> for some integer <em>m</em>.
Induction step: show that the assumption implies (<em>k</em> + 1)² - (<em>k</em> + 1) is also even. We have
(<em>k</em> + 1)² - (<em>k</em> + 1) = <em>k</em> ² + 2<em>k</em> + 1 - <em>k</em> - 1
… = (<em>k</em> ² - <em>k</em>) + 2<em>k</em>
… = 2<em>m</em> + 2<em>k</em>
… = 2 (<em>m</em> + <em>k</em>)
which is clearly even. QED
Answer:
x = 12
Step-by-step explanation:
Equation: 0.52(x) + 0.72(4) = 0.57(x + 4)
0.52(x) + 0.72(4) = 0.57(x + 4) 
Multiply
0.52x + 2.88 = 0.57x + 2.28 Subtract 0.52x from both sides
2.88 = 0.05x + 2.28 Subtract 2.28 from both sides
0.6 = 0.05x Divide all sides by 0.05
x = 12
-Chetan K
0.0246909 hope this helps love ❤️
