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Svetach [21]
3 years ago
6

How is the Distributive Property used to simplify operations with scientific notation

Mathematics
1 answer:
Citrus2011 [14]3 years ago
4 0

Answer:

See explanation

Step-by-step explanation:

Let a,b, and c be real numbers.

The distributive property says that:

a(b + c) = ab + ac

Assuming we want to simplify:

10(5*10^{-1}+150*10^{-3})

We apply the distributive property to get:

10(5*10^{-1}+150*10^{-3}) = 5*10^{-1} \times 10+150*10^{-3} \times 10

We can now use rules of exponents to simplify further:

10(5*10^{-1}+150*10^{-3}) = 5*10^{-1} \times 10^{1} +150*10^{-3} \times 10^{1}

10(5*10^{-1}+150*10^{-3}) = 5*10^{-1 + 1} +150*10^{-3 + 1}

10(5*10^{-1}+150*10^{-3}) = 5*10^{0} +150*10^{-2}

10(5*10^{-1}+150*10^{-3}) = 5*1+1.50*10^{-2}x {10}^{2}

10(5*10^{-1}+150*10^{-3}) = 5*1+1.50*10^{-2 + 2}

10(5*10^{-1}+150*10^{-3}) = 5+1.50*10^{0} = 6.5 \times  {10}^{0}

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Step-by-step explanation:

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4.) The time X (minutes) for a lab assistant to prepare the equipment for a certain experiment is believed to have a uniform dis
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Answer:

P(35-2 < X 35+2) = P(33< X< 37)= P(X

And using the cumulative distribution function we got:

P(35-2 < X 35+2) = P(33< X< 37)= P(X

The probability that preparation is within 2 minutes of the mean time is 0.134

Step-by-step explanation:

For this case we define the following random variable X= (minutes) for a lab assistant to prepare the equipment for a certain experiment , and the distribution for X is given by:

X \sim Unif (a= 20, b =50)

The cumulative distribution function is given by:

F(x) = \frac{x-a}{b-a} , a \leq X \leq b

The expected value is given by:

E(X) = \frac{a+b}{2} = \frac{20+50}{2}=35

And we want to find the following probability:

P(35-2 < X 35+2) = P(33< X< 37)

And we can find this probability on this way:

P(35-2 < X 35+2) = P(33< X< 37)= P(X

And using the cumulative distribution function we got:

P(35-2 < X 35+2) = P(33< X< 37)= P(X

The probability that preparation is within 2 minutes of the mean time is 0.134

8 0
3 years ago
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