180 + 30x = 60 + 50x
⇒ 20x = 120
⇒ x = 6 minutes
<span>it will take 6 minutes for Millie to catch up with Ben</span>
Answer:
D
Step-by-step explanation:
We want to find the distance between (-6, 4) and (-8, 6).
We can use the distance formula given by:

Let (-6, 4) be (x₁, y₁) and let (-8, 6) be (x₂, y₂).
Substitute:

Evaluate:

Evaluate:

Hence, our answer is D.
Answer:
find the classmark of each interval
- forexample
- (140+150)/2
- (150+160)/2
do the same up to (190+200)/2
then
draw a graph by using frequently (number of weeks) on y-axis against classmark on x-axis
I think it would be 324 divided by 4 = 81 in.
Answer:

Step-by-step explanation:
From the question we are told that:
Function given

Co-ordinates
(x,y)=[1, 4]
Generally the second differentiation of function is mathematically given by

Therefore critical point

Generally the substitutions of co-ordinate into function is mathematically given by
For 1

For 4

For critical point 3

Therefore the maximum value of f(x) = –x2 + 6x over the interval [1, 4] is given by
