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2 years ago

Definition: In x3, x is called the

Mathematics

1 answer:

Arturiano [62]2 years ago

3 0

Answer:

it is exponent less than 1

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What are the values of X and Z.

stiv31 [10]

Answer:

x = 12, z = 86

Step-by-step explanation:

Two angles are called supplementary when their measures add up to 180 degrees.

(12x -58 + 13x - 62 ) = 180°

12 x + 13x -58 - 62 = 180°

25x - 120 = 180

25x = 180 + 120

x = 300/ 25

x = 12

----------------------------------------------------------------------------------

(z° + 13x - 62) = 180

(z° + 13(12) - 62 )= 180

(z° + 156 - 62 )= 180

(z° + 94 ) = 180

z° = 180 - 94

z = 86

5 0

3 years ago

Sienna is solving the quadratic equation by completing the square.

pantera1 [17]

Answer:

See below

Step-by-step explanation:

3 (x^2 + 3x) = 4

3 ( x + 3/2)^2 = 4 + 27/4

4 0

1 year ago

Please help me out The equation 9(w + 7) = 27 solved in several steps below. For each step, choose the reason that best justifie

Vaselesa [24]

9w+63=27

27-63= -36

-36•/•9=-4

answer: -4=w

hope this helps

4 0

3 years ago

-4(7a+5) = -160 Show All Work!

Fynjy0 [20]

Answer:

a=-20

Step-by-step explanation:

-4(7a+5)=-160

7a+(-20)=-160 Multiply -4 and 5

7a=-140 Subtract -20 from -160

a=-20 Divide 7 by -140

7 0

2 years ago

What is an example of when you would want consistent data and, therefore, a small standard deviation?

steposvetlana [31]

Answer:

12.1, 12.3,12.4,12.5,12.3,12.1,12.2

$\bar X= \frac{12.1+12.3+12.4+12.5+12.3+12.1+12.2}{7}=12.271$

And for the standard deviation we can use the following formula:

$s= \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

And after replace we got:

$s = 0.1496$

And as we can ee we got a small value for the deviation <1 on this case.

Step-by-step explanation:

For example if we have the following data:

12.1, 12.3,12.4,12.5,12.3,12.1,12.2

We see that the data are similar for all the observations so we would expect a small standard deviation

If we calculate the sample mean we can use the following formula:

$\bar X=\frac{\sum_{i=1}^n X_i}{n}$

And replacing we got:

$\bar X= \frac{12.1+12.3+12.4+12.5+12.3+12.1+12.2}{7}=12.271$

And for the standard deviation we can use the following formula:

$s= \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

And after replace we got:

$s = 0.1496$

And as we can ee we got a small value for the deviation <1 on this case.

8 0

2 years ago