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sattari [20]
3 years ago
14

Elaine bought a total of 15 shirts and pairs of pants. She bought 7 more shirts than pants. How many of each did she buy.

Mathematics
1 answer:
zaharov [31]3 years ago
7 0

Answer:

4 pants 11 shirts

Step-by-step explanation:

4+11=15

11-4=7

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Tell whether the equation has the ordered pair as a solution y=6x; (-7,-42)
Ber [7]

Answer:

Yes

Step-by-step explanation:

Substituting in x = -7, we get y = 6(-7) = -42, which is the same as the y coordinate of the given point.

3 0
2 years ago
Please help me i need help
kenny6666 [7]

Answer:

H

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Step-by-step explanation:

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8 0
3 years ago
A community hall is shape of a cuboid. The hall is 40 m long, 15 m wide and 3 m high. The community hall needs re-decorating wit
Licemer1 [7]
Total cost for tiles and paints is $924.
Step-by-step explanation:
We have been given that a community hall is in the shape of a cuboid. The hall is 40m long 15m high and 3m wide.
The paint will be required for 4 walls and ceiling.
Let us find area of walls and ceiling.



Therefore, the area of walls and ceiling is 1410 square meters.
Given: Cost for 10 litre of paint is $10 and 10 litre paint covers 25 square meter. Therefore,


Therefore, the total painting cost is $564.
Tiles will be required for floor. Let us find the area of floor.


Given: 1m squared floor tiles costs $3. So,

Therefore, the total cost for tiles is $360.
Now let us find combined total cost of tiles and paint.

Therefore, the combined total cost of tiles and paint is $924.
3 0
2 years ago
Which of the following is the surface area of the right cylinder below?
Snowcat [4.5K]

Answer: Option A.

Step-by-step explanation:

You need to use this formula for calculate the surface area of the right cylinder:

SA=2\pi r^2+2\pi rh

Where "r" is the radius and "h" is the height.

You can identify in the figure that:

r=8units\\h=3units

Knowing this, you can substitute these values into the formula SA=2\pi r^2+2\pi rh, therefore you get that the surface area of this right cylinder is:

SA=2\pi (8units)^2+2\pi (8units)(3units)

SA=176\pi\ units^2

8 0
3 years ago
Neptune is an average distance of 4.5 × 10^9 km from the Sun. Estimate the length of the Neptunian year using the fact that the
zlopas [31]

Answer:

Answer:

164.32 earth year

Step-by-step explanation:

distance of Neptune, Rn = 4.5 x 10^9 km

distance of earth, Re = 1.5 x 10^8 km

time period of earth, Te = 1 year

let the time period of Neptune is Tn.

According to the Kepler's third law

T² ∝ R³

\left ( \frac{T_{n}}{T_{e}} \right )^{2}=\left ( \frac{R_{n}}{R_{e}} \right )^{3}

\left ( \frac{T_{n}}{1} \right )^{2}=\left ( \frac{4.5\times10^{9}}}{1.5\times10^{8}}} \right )^{3}

Tn = 164.32 earth years

Thus, the neptune year is equal to 164.32 earth year.

Step-by-step explanation:

3 0
3 years ago
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