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3 years ago

Elaine bought a total of 15 shirts and pairs of pants. She bought 7 more shirts than pants. How many of each did she buy.

Mathematics

1 answer:

zaharov [31]3 years ago

7 0

Answer:

4 pants 11 shirts

Step-by-step explanation:

4+11=15

11-4=7

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What is the value of c in the equation? 15.3 = StartFraction c Over 2.1 EndFraction 13.2 17.4 32.13 321.3

harina [27]

Answer:

32.13

Step-by-step explanation:

15.3= c/2.1

c= 15.3* 2.1

c= 32.13

3 0

3 years ago

Read 2 more answers

The San Andreas fault separates the pacific plates from the North America plate. The pacific plate moved northward relative to t

lesantik [10]

Answer:

The time, t it will take LA and San Francisco to be next to each other is 8,245,614.04 years which is over 8 million years

Step-by-step explanation:

The given parameters are;

The speed with which the pacific plate moved northward relative to the North American plate = 5.7 cm/year = 5.7 × 10⁻⁵ km/year

The distance between current LA and San Francisco = 470 km

From the formula for speed, s, we have

Speed = Distance/Time

Therefore, Time, t = Distance/Speed

The time, t it will take LA and San Francisco to be next to each other is given as follows;

t = (Distance between LA and San Francisco)/(The speed with which the pacific plate)

t = (470 km)/(5.7 cm/year) = 470/(5.7 × 10⁽⁻⁵⁾) = 8245614.04 years

Therefore, the time, t it will take LA and San Francisco to be next to each other is 8245614.04 years.

6 0

3 years ago

Let A = { x ∈ R : x 2 − 5 x + 4 ≤ 0 } , B = (3 , 5), and C = (3 , 4]. Show that A ∩ B = C . (Recall, you must show two separate

kolbaska11 [484]

Answer:

You can proceed as follows:

Step-by-step explanation:

First solve the quadratic inequality $x^{2}-5x+4\leq 0$ . To do that, factorize, then we have that $(x-4)(x-1)\leq 0$ . This implies that

$x-1\leq 0\, \text{and}\, x-4\geq 0$

$x-1 \geq 0\, \text{and}\, x-4\leq 0$

In the first case the solution is the empty set $\emptyset$ . In the second case the solution is the interval $1\leq x \leq 4$ . Now we have that

$A=[1,4]$

$B=(3,5)$

$C=(3,4]$ .

To show that $A\cap B\subseteq C$ consider $x\in A\cap B$ . Then $1\leq x \leq 4\, \text{and}\, 1$ , this implies that $3$ , then $x\in C$ . Now, to show that $C\subseteq A\cap B$ consider $x\in C$ , then $3$ , then $1\leq x \leq 4\, \text{and}\, 3$ , then $x\in [1,4] \, \text{and}\, x\in (3,5)$ , this implies that $x\in A\cap B$ .