Find the principal. Annual rate of interest= 11% Period=3 years Total interest= 825 rupees Principal rupees

The slope of the line passing through (-9,-6) and (-15,y) is 2/3. what is the value of y

Simora [160]

The value of y is -10

3 0

2 years ago

When Noah goes bowling, his scores are normally distributed with a mean of 150 and a standard deviation of 12. What is the proba

Zarrin [17]

Answer:

The probability of his score being between 135 and 167 is 0.8151 or (0.8151*100=81.51%)

Step-by-step explanation:

Given that:

Mean = μ = 150

SD = σ = 12

Let x1 be the first data point and x2 the second data point

We have to find the z-scores for both data points

x1 = 135

x2 = 167

So,

$z_1 = \frac{x_1-mean}{SD}\\= \frac{135-150}{12}\\=\frac{-15}{12}\\=-1.25$

And

$z_2 = \frac{x_2-mean}{SD}\\z_2 =\frac{167-150}{12}\\=\frac{17}{12}\\= {1.416}$

We have to find area to the left of both points then their difference to find the probability.

So,

Area to the left of z1 = 0.1056

Area to the left of z2 = 0.9207

Probability to score between 135 and 167 = z2-z1 = 0.9027-0.1056 = 0.8151

Hence,

The probability of his score being between 135 and 167 is 0.8151 or (0.8151*100=81.51%)

3 0

2 years ago

Find the volume of a right prism with height h=10 cm, if :

kozerog [31]

Answer:

Step-by-step explanation:

So, to begin the altitude of a triangle is the line segment that starts at the top vertex and ends at the base of the triangle forming a right angle. If we want to find the volume of the of the prism the formula is Ab*h. This is the area of the base, times the height of the prism. This is true because a simple expination of volume is a box filled with stuff. To count how much stuff we have in the box the formula uses layers. Volume is just like a lot of 2 dimential areas stacked on top of each other. So taking the area of the flat base and puting it on top of it self 10 time will give you the same prism thats in the problem. Now we just have to apply the consept. Since the base is a triangle and we need to find the area. The formula is b*h*1/2. Base time height times 1/2. The reason for this is also simlar to area. A triangle is half of a square, so to find the area of a square the formula is L*W. Since a triangle is half of a square you just multipuly it by 1/2. When solved you will get 4*3.5*1/2=7, the area of the base is 7 cm^2. Now appling the topic above we stack the base 10 times, so 7*10=70. In conculstion the volume of the prism would be 70 cm^2.

6 0

2 years ago

On a math quiz, Tina scored 5 less points than Ben. Juan scored

kumpel [21]

Answer:

a) t=b-5 b) j=b+3+2

Step-by-step explanation:

t is tina, we don't know how much Ben scored so we use b, then subtract 5 because tina got 5 less. same thing for Juan but we add the 3 points he got more than Ben and the 2 extra credit points

7 0

2 years ago

A solid is formed by adjoining two hemispheres to the ends of a right circular cylinder. An industrial tank of this shape must h

mestny [16]

Answer:

Radius =6.518 feet

Height = 26.074 feet

Step-by-step explanation:

The Volume of the Solid formed = Volume of the two Hemisphere + Volume of the Cylinder

Volume of a Hemisphere $=\frac{2}{3}\pi r^3$

Volume of a Cylinder $=\pi r^2 h$

Therefore:

The Volume of the Solid formed

$=2(\frac{2}{3}\pi r^3)+\pi r^2 h\\\frac{4}{3}\pi r^3+\pi r^2 h=4640\\\pi r^2(\frac{4r}{3}+ h)=4640\\\frac{4r}{3}+ h =\frac{4640}{\pi r^2} \\h=\frac{4640}{\pi r^2}-\frac{4r}{3}$

Area of the Hemisphere = $2\pi r^2$

Curved Surface Area of the Cylinder = $2\pi rh$

Total Surface Area=

$2\pi r^2+2\pi r^2+2\pi rh\\=4\pi r^2+2\pi rh$

Cost of the Hemispherical Ends = 2 X Cost of the surface area of the sides.

Therefore total Cost, C

$=2(4\pi r^2)+2\pi rh\\C=8\pi r^2+2\pi rh$

Recall: $h=\frac{4640}{\pi r^2}-\frac{4r}{3}$

Therefore:

$C=8\pi r^2+2\pi r(\frac{4640}{\pi r^2}-\frac{4r}{3})\\C=8\pi r^2+\frac{9280}{r}-\frac{8\pi r^2}{3}\\C=\frac{9280}{r}+\frac{24\pi r^2-8\pi r^2}{3}\\C=\frac{9280}{r}+\frac{16\pi r^2}{3}\\C=\frac{27840+16\pi r^3}{3r}$

The minimum cost occurs at the point where the derivative equals zero.

$C^{'}=\frac{-27840+32\pi r^3}{3r^2}$

$When \:C^{'}=0$

$-27840+32\pi r^3=0\\27840=32\pi r^3\\r^3=27840 \div 32\pi=276.9296\\r=\sqrt[3]{276.9296} =6.518$

Recall:

$h=\frac{4640}{\pi r^2}-\frac{4r}{3}\\h=\frac{4640}{\pi*6.518^2}-\frac{4*6.518}{3}\\h=26.074 feet$

Therefore, the dimensions that will minimize the cost are:

Radius =6.518 feet

Height = 26.074 feet

5 0

2 years ago

Find the principal. Annual rate of interest= 11% Period=3 years Total interest= 825 rupees Principal rupees​

Find the principal. Annual rate of interest= 11% Period=3 years Total interest= 825 rupees Principal rupees