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3 years ago

What is a balanced equation for the neutralization of these two compounds? HCl Ca(OH)2

1 answer:

8 0

In order to balance this, you have to count each element where the elements in the reactants side and the product side should have equal number of molecules. The balanced reaction is as follows:

2HCl + Ca(OH)2 = CaCl2 + 2H2O

You might be interested in

Indicate whether the following are acidic, basic, or neutral solution

goldenfox [79]

You answer this by using the pH formula and and the relation of pH and pOH, pH = -log[H+] and 14 = pH + pOH. The correct classification are as follows:

<span>A. [H2O+]=6.0x10^-12
basic

B. [H3O+]=1.4x10^-9
basic

C. [OH-]=5.0x10^-12
acidic

D. {OH-]=3.5x10^-10
acidic

Hope this answers the question.

</span>

5 0

3 years ago

In a transverse wave that travels through a medium, the molecules of the medium vibratea. at twice the velocity of the molecules

viktelen [127]

B. at a right angle to the wave's direction

8 0

3 years ago

How is chemical and physical properties of matter like in different

Tasya [4]

Chemical properties is when a material undergoes a chemical change or reaction like a nail rusting and a physical change can be observed without changing the material like temperature, color, texture, odor,etc.

4 0

3 years ago

Which would be the best way to represent the concentration of a 1. 75 M K2CrO4 solution? 1. 75% K2CrO4 [K2CrO4] (K2CrO4) K2CrO4,

tekilochka [14]

The amount of the solute present in the given solution is called the concentration. The best way to represent the concentration of the solution is $\rm [K_{2}CrO_{4}].$

<h3>What is molar concentration?</h3>

Molar concentration is the molarity of the solution that is the measure of the concentration of the solute dissolved in the solution.

The formula for calculating molar concentration is given as,

$\rm Molarity = \dfrac{\text{moles of solute}}{\text{Solution in L}}$

The concentration of any substance is represented in the square bracket like $\rm [X]$ or $\rm [K_{2}CrO_{4}].$

Therefore, option B. $\rm [K_{2}CrO_{4}]$ is the representation of the concentration.

Learn more about the molarity here:

brainly.com/question/1532164

8 0

2 years ago

A 1.42-g sample of a pure compound with formula m2so4 was dissolved in water and treated with an ex- cess of aqueous calcium chl

solong [7]

The reaction between $m_{2}SO_{4}$ with calcium chloride can be shown as- $m_{2}SO_{4}$ + $CaCl_{2}$ → $CaSO_{4}$ ↓+2mCl. The molecular weight of $CaSO_{4}$ is 136.14g. The weight of sulfate ion is 96.06g. The molecular weight of $m_{2}SO_{4}$ = (2×m + 96.06). From the reaction we can see that 1 mole of calcium chloride reacts with 1 moles $m_{2}SO_{4}$ to produce 1 mole of calcium sulfate. Now 1.36g of calcium sulfate is equivalent to 1.36/136.14=9.989× $10^{-3}$ moles of calcium sulfate.

Thus, 9.989× $10^{-3}$ moles of $m_{2}SO_{4}$ reacts in this reaction.

Let assume the atomic mass of m is x thus the molecular weight of $m_{2}SO_{4}$ is 2x+96.

So we may write 9.989× $10^{-3}$ × (2x+96) =1.42

Or, 2x + 96 = 142.146

Or, 2x = 46.146

Or, x = 23.073

Thus the atomic mass of m is 23.073. The atom (m) is sodium (Na).

8 0

3 years ago