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3 years ago

Look at the equation CO2+H2 CO+H2O. CO is a _____.

Chemistry

2 answers:

antoniya [11.8K]3 years ago

7 0

<u>Answer:</u> CO is considered as a product.

<u>Explanation:</u>

A general chemical equation for a combination reaction follows:

$A+B\rightarrow C$

To write a chemical equation, we must follow some of the rules:

The reactants must be written on the left side of the direction arrow.
A '+' sign is written between the reactants, when more than one reactants are present.
An arrow is added after all the reactants are written in the direction where reaction is taking place. Here, the reaction is taking place in forward direction.
The products must be written on the right side of the direction arrow.
A '+' sign is written between the products, when more than one products are present.

For the given chemical equation:

$CO_2+H_2\rightarrow CO+H_2O$

$CO_2\text{ and }H_2$ are the reactants in the reaction and $CO\text{ and }H_2O$ are the products in the reaction.

Hence, CO is considered as a product.

Troyanec [42]3 years ago

4 0

Carbon monoxide gas 20 characters

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If 6.2 mold of H2SO4 is dissolved to make 750 ml of sulfuric acid what is the molarity

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Answer: The molarity of given solution is 8.26 M.

Explanation:

Given: No. of moles = 6.2 mol

Volume = 750 mL (1 mL = 0.001 L) = 0.75 L

Molarity is the number of moles of a substance present in a liter of solution.

Therefore, molarity of given solution is converted as follows.

$Molarity = \frac{no. of moles}{Volume (in L)}\\= \frac{6.2 mol}{0.75 L}\\= 8.26 M$

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3 years ago

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Why are unbalanced equations NOT useful in<br> chemistry?

Nimfa-mama [501]

Answer:

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3 years ago

Rank the following gases in order of decreasing rate of effusion. Rank from the highest to lowest effusion rate. To rank items a

Alinara [238K]

Answer:

H2, He, PH3, F2, C5H10

Explanation:

From Graham's law, we understood that lighter gas will diffuse faster than heavier gas under same condition. Graham's law of diffusion states as follow:

The rate (R) of diffusion of a gas is inversely proportional to the square root of its density (D) provided temperature and pressure remains constant. Mathematically, it is represented as:

R & 1/√D

Recall:

Molar Mass (M) = 2 x vapour density (D)

M = 2D

R & 1/√M

From the above, we can see that the rate is inversely proportional to the square root of the molar mass of substance. This implies that lighter gas will diffuse faster.

Now, to rank the above from the highest to rate rate of effusion, let us determine the molecular weight of each substance. This is illustrated below:

Molar Mass of F2 = 19 x 2 = 38g/mol

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Molar Mass of C5H10 = (12X5) + (10X1) = 70g/mol

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Now, we can rank the substance beginning from the highest to the lowest rate of effusion as follow:

Substance >> Molar Mass >> Rank

H2 >>>>>>>>> 2g/mol >>>>>> 1

He >>>>>>>>> 4g/mol >>>>>> 2

PH3 >>>>>>>> 34g/mol >>>>> 3

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3 0

3 years ago

Use the reaction and bond information to answer the question. H2 CO2 → CH2O2 Reactant bond energies: H–H is 432 kJ/mol, C=O is 7

Anna11 [10]

The energy absorbed by the system before the reaction start has been 752 kJ/mol.

The bond energy has been defined as the energy possessed by the bond that has been converted into the heat energy and utilized in the reaction.

The energy has been conserved in a chemical reaction. Thus, the energy absorbed by the reactant in the reaction has been the difference in the energy of the reactant and product.

<h3>Computation for the energy absorbed</h3><h3 />

The given reaction has been:

$\rm H_2\;+\;CO_2\;\rightarrow\;CH_2O_2$

The bond energy of the reactant has been:

H-H bond energy = 432 kJ/mol

2 C=O bond energy= 799 kJ/mol

The total energy of the reactant has been 432 kJ/mol + 799 kJ/mol

The total energy of the reactant has been 1231 kJ/mol

The bond energy of the product has been:

C-O bonds = 358 kJ/mol

C=O bonds = 745 kJ/mol

1 C-H bond = 413 kJ/mol

1 O-H bond = 467 kJ/mol

The total energy of the product has been 358 + 745 + 413 + 467 kJ/mol

The total energy of the product has been 1,983 kJ/mol

According to the law of conservation of energy:

$\text{Product energy=Reactant energy + energy absorbed}$

Substituting the values for energy absorbed:

$\text{1,983 kJ/mol=1231\;kJ/mol+ energy absorbed}\\\rm Energy\;absorbed=1983-1231\;kJ/mol\\Energy\;absorbed=752\;kJ/mol$

The energy absorbed by the system before the reaction start has been 752 kJ/mol.

Learn more about bond energy, here:

brainly.com/question/866298

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2 years ago