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MrMuchimi
3 years ago
7

The weight of the buggy was 40N on Mars. When the buggy landed on Mars it rested on an area of 0.025 m2. Calculate the pressure

exerted by the buggy on the surface of Mars
Chemistry
1 answer:
elena-s [515]3 years ago
4 0

Answer:

The pressure exerted by the buggy on the surface of Mars is 1600 pascals.

Explanation:

The pressure is determined by the definition of stress, which is the force exerted by the buggy on the martian surface divided by the contact area of the latter:

\sigma = \frac{F}{A}

Where:

\sigma - Stress, measured in pascals.

F - Force, measured in newtons.

A - Area, measured in square meters.

The force is the weight of the buggy (40 N) and A = 0.025\,m^{2}, the stress is now calculated:

\sigma = \frac{40\,N}{0.025\,m^{2}}

\sigma = 1600\,Pa

The pressure exerted by the buggy on the surface of Mars is 1600 pascals.

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