Answer:
Since you are producing 3.6 mol CO2, you can calculate the starting moles of CH4 with the simple mole-to-mole ratio: 1 mol CH4 / 1 mol CO2 as a conversion factor. Taking 3.6 mol CO2 x 1 mol CH4 / 1 mol CO2 = 3.6 mol CH4 (after canceling out the moles of CO2 on the top and bottom of the calculation)
Explanation:
Answer:
4046atm
Explanation:
For this question you can use the ideal gas law,
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Where P is pressure, V is volume, n is moles of substance, R is the constant, and T is the temperature.
Because of the units given, R will equal .08026
<h3>Rearrange the equation to solve for pressure:</h3>

Then, plug in the values (I'll be excluding units for simplicity, but they all cancel out for pressure in atm):

This will give you:

Answer:
fundamental frequency in helium = 729.8 Hz
Explanation:
Fundamental frequency of an ope tube/pipe = v/2L
where v is velocity of sound in air = 340 m/s; λ is wave length of wave = 2L ; L is length of the pipe
To find the length of the pipe,
frequency = velocity of sound / 2L
272 = 340 / 2 L
L = 0.625 m
If the pipe is filled with helium at the same temperature, the velocity of sound will change as well as the frequency of note produced since velocity is directly proportional to frequency of sound.
Also, the velocity of sound is inversely proportional to square root of molar mass of gas; v ∝ 1/√m
v₁/v₂ = √m₂/m₁
v₁ = velocity of sound in air, v₂ = velocity of sound in helium, m₁ = molar mass of air, m₂ = molar mass of helium
340 / v = √4 / 28.8
v₂ = 340 / 0. 3727
v₂ = 912.26 m /s
fundamental frequency in helium = v₂ / 2L
fundamental frequency in helium = 912.26 / (2 x 0.625)
fundamental frequency in helium = 729.8 Hz
Answer:
≈ 395,8 J/(kg * °C)
Explanation:
m = 44 g = 0,044 kg
= 22 °C
= 33,6 °C
Q = 202 J
The formula is: Q = c * m * (
)
c =
Calculating:
c = 202 J / 0,044 kg * (33,6 °C - 22 °C) ≈ 395,8 J/(kg * °C)