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MrMuchimi
4 years ago
7

The weight of the buggy was 40N on Mars. When the buggy landed on Mars it rested on an area of 0.025 m2. Calculate the pressure

exerted by the buggy on the surface of Mars
Chemistry
1 answer:
elena-s [515]4 years ago
4 0

Answer:

The pressure exerted by the buggy on the surface of Mars is 1600 pascals.

Explanation:

The pressure is determined by the definition of stress, which is the force exerted by the buggy on the martian surface divided by the contact area of the latter:

\sigma = \frac{F}{A}

Where:

\sigma - Stress, measured in pascals.

F - Force, measured in newtons.

A - Area, measured in square meters.

The force is the weight of the buggy (40 N) and A = 0.025\,m^{2}, the stress is now calculated:

\sigma = \frac{40\,N}{0.025\,m^{2}}

\sigma = 1600\,Pa

The pressure exerted by the buggy on the surface of Mars is 1600 pascals.

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What mass of hydrogen sulfide, H2S, will completely react with 2.00 moles of silver nitrate, AgNO3?
hodyreva [135]

Answer:

34g

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

H2S + 2AgNO3 —> 2HNO3 + Ag2S

Next, we shall determine the number of mole of H2S required to react with 2 moles of AgNO3.

This is illustrated below:

From the balanced equation above,

We can see that 1 mole of H2S is required to react completely with 2 moles of AgNO3.

Finally, we shall convert 1 mole of H2S to grams. This is shown below:

Number of mole H2S = 1 mole

Molar mass of H2S = (2x1) + 32 = 34g/mol

Mass = number of mole x molar Mass

Mass of H2S = 1 x 34

Mass of H2S = 34g

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Answer:

<em>Thioesters- the Sulfur-Carbon bond is hydrolyzed, e.g. AcetylCoA</em>

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Explanation:

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Match.
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Answer:

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A solution is made up of 0.15 grams of sodium chloride in 1 liter of water. For this solution, the Solvent is water.  When water is present, it is usually considered the solvent.

A solution is made up of 0.15 grams of sodium chloride in 1 liter of water. For this solution, the Solute is sodium chloride.  There can be 1 or more solutes in a solution.

If you place 5 moles of sodium chloride and 4 moles of sucrose into 11 moles of water, the Mole fraction of sodium chloride would be 0.25.  The mole fraction is equal to the moles of a substance divided by the total number of moles.

A way to express concentration that provides the moles of solute per liter of solution is Molarity.

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