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3 years ago

How are cistrans isomers used for night vision?

Chemistry

1 answer:

Paladinen [302]3 years ago

7 0

Qual das alternativas a seguir é uma mistura homogênea?

Escolha uma:a. Mercúrio metálico e água. b. Gelo e água líquida. c. Areia e carvão em pó. d. Nitrogênio gasoso e vapor d’água. e. Poeira e ar atmosférico.

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Pls help. the picture is above. thanks!!

Mrac [35]

I believe it is none of the above are polar

8 0

3 years ago

(20 points) i) An absorption intensity of 1.00 (in arbitrary units) is observed for the maximum peak of the 1:2:1 triplet of the

laiz [17]

Answer:

Concentration of ethanol required = 48.476 M

Explanation:

Given that:

the absorption intensity = 1.00

Molarity of ethanol = 1M

NMR instrument used = 160 MHz

Temperature used = 300 K

The required concentration of ethanol can be determined as follows:

$= ( 1 \ M \times \dfrac{160\ MHz }{450 \ MHz}) \times \dfrac{300 \ K}{2.2\ K}$

$= ( 1 \ M \times 0.3555 ) \times136.36}$

= 48.476 M

5 0

3 years ago

Magsalaysay Ng pangyayari batay sa iyong unang karanasan halimbawa nang ika'y naligaw.

Akimi4 [234]

Answer:

67r7e5e7eq5st

Explanation:

3 0

3 years ago

Strontium chlorate is mixed with ammonium phosphate

lana [24]

Explanation:

Please, if I may ask, what is the exact question?

5 0

3 years ago

238 U 92 write the following decay sequence.

Vladimir [108]

Answer: The given decay sequence is $^{238}_{92}U \rightarrow ^{234}_{90}Th + ^{4}_{2}He \rightarrow ^{234}_{91}Pa + ^{0}_{-1}\beta$ .

Explanation:

An alpha-particle is a helium atom. Hence, when an alpha decay occurs in $^{238}_{92}U$ then the reaction equation is as follows.

$^{238}_{92}U \rightarrow ^{234}_{90}Th + ^{4}_{2}He$

Now, in sequence the equation for beta decay is as follows.

$^{234}_{90}Th \rightarrow ^{234}_{91}Pa + ^{0}_{-1}\beta$

Hence, the sequence will be as follows.

$^{238}_{92}U \rightarrow ^{234}_{90}Th + ^{4}_{2}He \rightarrow ^{234}_{91}Pa + ^{0}_{-1}\beta$

Thus, we can conclude that the given decay sequence is $^{238}_{92}U \rightarrow ^{234}_{90}Th + ^{4}_{2}He \rightarrow ^{234}_{91}Pa + ^{0}_{-1}\beta$ .

4 0

3 years ago