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lina2011 [118]
3 years ago
14

____________ are solutions that resist changes in ph when moderate amounts of acids or bases are added and contain ions or molec

ules that react with oh- or h when these ions are introduced into solution.
Chemistry
1 answer:
Kaylis [27]3 years ago
5 0
<u><em>Buffers</em></u> <span>are solutions that resist changes in ph when moderate amounts of acids or bases are added and contain ions or molecules that react with oh- or h when these ions are introduced into solution.</span>
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in the reaction C5H8 ____02--8H20, what coefficient should be placed in frount of 02 to balance the reaction?
Gekata [30.6K]
5CO2 should be in the blank spot.

the reaction would be 7
7 0
3 years ago
Applying the rules of significant figures, which of the following would be the correct value for the density of a substance whic
lilavasa [31]

16 g/ml

<h3>Further explanation</h3>

Given

mass = 32.40 g

volume = 2.0mL

Required

Density

Solution

Density is a quantity derived from the mass and volume  

Density is the ratio of mass per unit volume  

Density formula:  

\large {\boxed {\bold {\rho ~ = ~ \frac {m} {V}}}}

ρ = density  

m = mass  

v = volume  

Input the value :

ρ = 32.40 g / 2.0 ml

ρ = 16.2 g/ml

Rules for division: The least number of significant figures in the problem determines the number of significant figures in the answer.

32.40 = 4 sig.fig

2.0 = 2 sig fig

The answer must be 2 sig fig

So the answer = 16 g/ml

6 0
3 years ago
Given the solubility, calculate the solubility product constant (ksp) of each salt at 25°c: (a) pbcro4, s = 4.0 × 10−5 g/l; (b)
madreJ [45]
a) PbCrO4:

according to the equation:

PbCrO4(s)  →  Pb2+(aq)   +  CrO42-(aq)

so, Ksp = [Pb2+][CrO42-]

by assuming [Pb2+] = [CrO42-] = X

and when S (the solubility) = 4 x 10^-5 g/L

we have first to convert solubility from g/L to mol/L by getting the molar mass of the salt 

solubility mol/L =  solubility g/L / molar mass of salt

                           = 4 x 10^-5g/L / 323.2 g/mol

                            = 1.24 x 10^-7 mol / L

by substitution in Ksp formula:

∴Ksp = X* X

         = (1.24 x 10^-7)^2

         = 1.54 x 10^-14

b) BaC2O4:

according to this equation:

BaC2O4(s)→  Ba 2+(aq)  +  C2O4 2- (aq)  

So Ksp = [Ba2+][C2O42-]

Assume that [Ba2+] = [C2O42-] = X

when the solubility S =  0.29 g/L = X  , so we need to convert S from g/L to
mol / L 

solubility mol / L= solubility g/L / molar mass of salt

                           = 0.29 g/L / 225.34 g/mol

                           = 0.0013 mol/L

by substitution in ksp formula:

∴Ksp = X^2 

         = (0.0013)^2 

         = 1.69 x 10^-6 

C)  MnCO3: 

according to this equation :

MnCO3(s)→ Mn2+(aq)   +  CO3 2-(aq)

so, Ksp = [Mn2+][CO32-]

assume [Mn2+] = [CO32-] = X

when the solubility s = 4.2 x 10^-6 g/L so we need to convert S from g/L to mol/L by dividing on molar mass.

the solubility mol/L = solubility g/L / molar mass g/mol

                                 =.4.2 x 10^-6 /114.9 

                                 = 3.7 x 10^-8 mol/L

by substitution on ksp formula:

∴ Ksp = X*X

           = (3.7 x 10^-8)^2

           = 1.369 x 10^-15
6 0
3 years ago
What is the relationship between the concentration and the rate of the reaction?
zalisa [80]

Answer:

When the concentration of all the reactants increases, more molecules or ions interact to form new compounds, and the rate of reaction increases. When the concentration of a reactant decreases, there are fewer of that molecule or ion present, and the rate of reaction decreases.

3 0
3 years ago
A weak monoprotic acid has molar mass 180 g/mol. When 1.00 g of this acid is dissolved in enough water to obtain a 300 mL soluti
Kaylis [27]

<u>Answer:</u> The value of K_a for the given acid is 3.58\times 10^{-4}

<u>Explanation:</u>

To calculate the molarity of solution, we use the equation:

\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}

Initial mass of weak monoprotic acid = 1.00 g

Molar mass of weak monoprotic acid = 180 g/mol

Volume of solution = 300 mL

Putting values in above equation, we get:

\text{Molarity of weak monoprotic acid}=\frac{1.00\times 1000}{180\times 300}\\\\\text{Molarity of weak monoprotic acid}=0.0185M

To calculate the hydrogen ion concentration for given pH of the solution, we use the equation:

pH=-\log[H^+]

We are given:

pH = 2.62

Putting values in above equation, we get:

2.62=-\log[H^+]

[H^+]=10^{-2.62}=2.40\times 10^{-3}M=0.0024M

The chemical equation for the dissociation of weak monoprotic acid (HA) follows:

                            HA\rightleftharpoons H^++A^-

<u>Initial:</u>              0.0185

<u>At eqllm:</u>        0.0185-x     x     x

Evaluating the value of 'x'

\Rightarrow x=0.0024

So, equilibrium concentration of HA = (0.0185 - 0.0024) = 0.0161 M

Equilibrium concentration of A^- = x = 0.0024 M

The expression of K_a for above equation follows:

K_a=\frac{[H^+][A^-]}{[HA]}

Putting values in above equation, we get:

K_a=\frac{(0.0024)\times (0.0024)}{0.0161}=3.58\times 10^{-4}

Hence, the value of K_a for the given acid is 3.58\times 10^{-4}

5 0
4 years ago
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