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horsena [70]
3 years ago
10

What is the range for the function f(x)=^3/×

Mathematics
1 answer:
Galina-37 [17]3 years ago
5 0
M=ch x 4 next 3 = mch (34)
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I need help with this
emmasim [6.3K]

Answer:

Here,

Angle TUV + Angle NUV=TUV

By substituting the provided or given value ls in the question we obtain,

1+38x+66 Degree= 105x

1+66 Degree= 67x

67 Degree= 67x

1 Degree = x

x = 1 Degree

Therefore

Angle TUN=1+38x=39

Angle NUV=66 Degree

Therefore

1+38x+66 Degree= 105x

=39 Degree+66 Degree= 105 Degree

Therefore

Angle TUV=105 Degree

6 0
3 years ago
To which graph does the point (8,-2) belong?
Phoenix [80]
Where is the picture ?
8 0
3 years ago
In a random sample of 80 teenagers, the average number of texts handled in a day is 50. The 96% confidence interval for the mean
Nastasia [14]

Answer:

a) \bar X =\frac{46+54}{2}=50

And the margin of error is given by:

ME= \frac{54-46}{2}= 4

The confidence level is 0.96 and the significance level is \alpha=1-0.96=0.04 and the value of \alpha/2 =0.02 and the margin of error is given by:

ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}

We can calculate the critical value and we got:

z_{\alpha/2} = 2.05

And if we solve for the deviation like this:

\sigma = ME * \frac{\sqrt{n}}{z_{\alpha/2}}

And replacing we got:

\sigma =4 *\frac{\sqrt{80}}{2.05} =17.45

b) ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}=2.05 *\frac{17.45}{\sqrt{160}}=2.828

And as we can see that the margin of error would be lower than the original value of 4, the margin of error would be reduced by a factor \sqrt{2}

Step-by-step explanation:

Previous concepts  

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

\bar X represent the sample mean  

\mu population mean (variable of interest)  

\sigma represent the population standard deviation  

n=80 represent the sample size  

Solution to the problem

Part a

The confidence interval for the mean is given by the following formula:  

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}} (1)  

For this case we can calculate the mean like this:

\bar X =\frac{46+54}{2}=50

And the margin of error is given by:

ME= \frac{54-46}{2}= 4

The confidence level is 0.96 and the significance level is \alpha=1-0.96=0.04 and the value of \alpha/2 =0.02 and the margin of error is given by:

ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}

We can calculate the critical value and we got:

z_{\alpha/2} = 2.05

And if we solve for the deviation like this:

\sigma = ME * \frac{\sqrt{n}}{z_{\alpha/2}}

And replacing we got:

\sigma =4 *\frac{\sqrt{80}}{2.05} =17.45

Part b

For this case is the sample size is doubled the margin of error would be:

ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}=2.05 *\frac{17.45}{\sqrt{160}}=2.828

And as we can see that the margin of error would be lower than the original value of 4, the margin of error would be reduced by a factor \sqrt{2}

5 0
3 years ago
I need help 3rd try on Ttm lesson
Natasha2012 [34]
The answer is 2900mg because you have to divide the two numders
5 0
3 years ago
10. An arithmetic sequence has this recursive formula. What is the explicit formula?​
Mrrafil [7]

Answer:

a_{n}=45-3n

Step-by-step explanation:

Method 1:

Arithmetic sequence is in the form

a_{n} =a_{1} +(n-1)d\\

d is the common difference, can be found by:

d=a_{n}-a_{n-1}=-3

Subtituting the a_{1} and d

You get:

a_{n}=42+(-3)(n-1)=45-3n

Method 2 (Mathematical induction):

Assume it is in form a_{n}=45-3n

Base step: a_{1} =45-3(1)=42

Inducive hypophesis: a_{n}=45-3n

GIven: a_{n+1} =a_{n}-3

a_{n+1}=45-3n-3=45-3(n+1)

Proved by mathematical induction

a_{n}=45-3n

5 0
3 years ago
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