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enyata [817]
3 years ago
5

How many megagrams are there in 7.020 * 10^-10 nanograms

Chemistry
2 answers:
Aleonysh [2.5K]3 years ago
7 0
<span>7.020 * 10^-25
 There are 15 orders of magnitude between megagrams and nanograms Megagram = 1 x 10^6 gram
 Nanogram = 1 x 10^-9 gram</span>
Ilia_Sergeevich [38]3 years ago
5 0
From the basics conversions:
1 nanogram is equivalent to 1 * 10^-15 megagrams

To convert 7.02 * 10^-10 nanograms to megagrams, all you have to do is cross multiplication as follows:
1 nanogram ................> 1 * 10^-15 megagrams
7.02 * 10^-10 nanograms ...............> ?? megagrams

megagrams = (7.02*10^-10 * 1*10^-15) / (1) = 7.02 * 10^-25 megagrams
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Answer:

The correct alternative is "Option a".

Explanation:

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Other possibilities are not connected to the scenario in question. So Choice A is the best option.

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Find the area given rectangle.
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3 0
3 years ago
The enthalpy of solution (∆H) of KOH is -57.6 kJ/mol. If 3.66 g KOH is dissolved in enough water to make a 150.0 mL solution, wh
Wewaii [24]

When 3.66 g of KOH (∆Hsol = -57.6 kJ/mol) is dissolved in 150.0 mL of solution, it causes a temperature change of 5.87 °C.

The enthalpy of solution of KOH is -57.6 kJ/mol. We can calculate the heat released by the solution (Qr) of 3.66 g of KOH considering that the molar mass of KOH is 56.11 g/mol.

3.66g \times \frac{1mol}{56.11g} \times \frac{(-57.6kJ)}{mol} = -3.76 kJ

According to the law of conservation of energy, the sum of the heat released by the solution of KOH (Qr) and the heat absorbed by the solution (Qa) is zero.

Qr+Qa = 0\\\\Qa = -Qr = 3.76 kJ

150.0 mL of solution with a density of 1.02 g/mL were prepared. The mass (m) of the solution is:

150.0 mL \times \frac{1.02g}{mL}  = 153 g

Given the specific heat capacity of the solution (c) is 4.184 J/g・°C, we can calculate the change in the temperature (ΔT) of the solution using the following expression.

Qa = c \times m \times \Delta T\\\\\Delta T = \frac{Qa}{c \times m} = \frac{3.76 \times 10^{3}J  }{\frac{4.184J}{g.\° C }  \times 153g} = 5.87 \° C

When 3.66 g of KOH (∆Hsol = -57.6 kJ/mol) is dissolved in 150.0 mL of solution, it causes a temperature change of 5.87 °C.

Learn more: brainly.com/question/4400908

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2 years ago
the trend for ionization energy is a general increase from left to right across a period. However phosphorus is found to have hi
dimaraw [331]
Since phosphorus is in the 5th group it has the ability to gain or lose electrons
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3 years ago
Which reaction takes place in a nuclear fission reactor?
Marat540 [252]

The reaction that takes place in a nuclear fission reactor is as follows: 235/92 U + 1/0n 94/36Kr + 139/56 Ba + 3/0n.

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Nuclear fission is the nuclear reaction in which a large nucleus splits into smaller ones with the simultaneous release of energy.

Therefore, the option that involves the splitting of atoms into smaller ones is as follows: 235/92 U + 1/0n 94/36Kr + 139/56 Ba + 3/0n.

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