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kicyunya [14]
3 years ago
6

How would you prepare 50.0 ml of 0.600 m hno3 from a stock solution of 4.00 m hno3? what volume (in ml) of the 4.00 m hno3 solut

ion will you need?
Chemistry
1 answer:
serg [7]3 years ago
5 0
It will need 40000ml of the solution.
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Decide whether the compound is ionic or molecular, if you can.
Aleks [24]

Answer:

Ionic solid

Explanation:

Ionic solids are known to be hard solids. They do not conduct electricity in the solid state, however the solution of the solid or it's melt conducts electricity.

Ionic solids have a very high melting point due to strong ion-ion interaction. Hence the high melting point of this solid.

3 0
3 years ago
5. Identify each of the following as an element, a mixture, or a compound.
VashaNatasha [74]

Answer:

Aluminum foil ~ element

Air ~ mixture

Water ~ compound

Salt Water ~ mixture

Copper Wire ~ element

Steel ~ element

4 0
3 years ago
0.0136 g + 2.70 × 10-4 g - 4.21 × 10-3 g = ? How many digits to the right of the decimal point should be used to report the resu
ki77a [65]

Consider the following equation:0.0136 g + 2.70 × 10-4 g - 4.21 × 10-3 g  = ? How many digits to the right of the decimal point should be used to report the result? =2, Choose the correct answer=9.66 × 10^-3 g, Which metric unit would be the best choice to report the result?=mg

4 0
3 years ago
Read 2 more answers
How many atoms are there in 7.80 moles of germanium
Orlov [11]
<h3>Answer:</h3>

4.70 × 10²⁴ atoms Ge

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Using Dimensional Analysis
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
<h3>Explanation:</h3>

<u>Step 1: Define</u>

7.80 mol Ge

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

\displaystyle 7.80 \ mol \ Ge(\frac{6.022 \cdot 10^{23} \ atoms \ Ge}{1 \ mol \ Ge} ) = 4.69716 × 10²⁴ atoms Ge

<u>Step 4: Check</u>

<em>We are given 3 sig figs. Follow sig fig rules and round.</em>

4.69716 × 10²⁴ atoms Ge ≈ 4.70 × 10²⁴ atoms Ge

8 0
2 years ago
My test is tomorrow and I'm confused about how to solve these. pls halp
Stels [109]

Answer:

Explanation:

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5 0
2 years ago
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