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2 years ago

Which of the following is fact-based science rather than part of a belief system

Chemistry

2 answers:

makkiz [27]2 years ago

6 0

Answer:

c. chemistry

Explanation:

it uses science and math which are based on facts.

Bezzdna [24]2 years ago

5 0

Answer:

The correct answer will be option-C.

Explanation:

The aim of scientific investigations is to understand and explain the natural phenomenon. This aim can be achieved by using the scientific methods which provide the pieces of evidence to explain and understand the natural events.

The scientific investigation is not based on the belief system, personal opinions and the co-incidences which cannot explain the natural phenomenon. They are considered as a part of the pseudoscience practice as they lack evidence.

Since chemistry is the field of study which can explain any natural phenomenon by performing an experiment which provides evidence, therefore, Option-C is the correct answer.

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Answer:

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Explanation:

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3 years ago

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2 years ago

Read 2 more answers

Polyester is a synthetic material used for many different purposes. It is produced from petroleum and natural gas. Producing pol

notka56 [123]

Answer:

A. Producing certain synthetic materials could have a greater environmental impact than disposing of them.

Explanation

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3 0

1 year ago

Calcule la densidad del hidrógeno H2 en g/L a 327 mm Hg y 48ºc

tankabanditka [31]

<h3>The density of H₂ = 0.033 g/L</h3><h3>Further explanation</h3>

In general, the gas equation can be written

$\large {\boxed {\bold {PV = nRT}}}$

where

P = pressure, atm , N/m²

V = volume, liter

n = number of moles

R = gas constant = 0.082 l.atm / mol K (P= atm, v= liter),or 8,314 J/mol K (P=Pa or N/m², v= m³)

T = temperature, Kelvin

n = N / No

n = mole

No = Avogadro number (6.02.10²³)

n = m / MW

m = mass

MW = molecular weight

For density , can be formulated :

$\tt \rho=\dfrac{P\times MW}{R\times T}$

P = 327 mmHg = 0,430263 atm

R = 0.082 L.atm / mol K

T = 48 ºC = 321.15 K

MW of H₂ = 2.015 g/mol

The density :

$\rho=\dfrac{0,430263\times 2.015 }{0.082\times 321.15}\\\\\rho=0.033~g/L$

4 0

2 years ago

Estimate the molar mass of a gas that effuses at 1.6 times the effusion rate of CO2

Vlada [557]

To estimate the molar mass of the gas, we use Graham's law of effusion. This relates the rates of effusion of gases with their molar mass. We calculate as follows:

r1/r2 = √(m2/m1)

where r1 would be the effusion rate of the gas and r2 is for CO2, M1 is the molar mass of the gas and M2 would be the molar mass of CO2 (44.01 g/mol)

r1 = 1.6r2

1.6 = √(44.01 / m1)
m1 = 17.19 g/mol

7 0

2 years ago