In order to solve this mathematical problem we can first
consolidate and observe the given values and the values that are not known in
the stated problem.
Annie traveled 5 times the sum of the number of hours Brian
traveled and 2. Together they traveled 20 hours. Find the numbers.
Equation,
<span><span> 1. </span><span> 5(y) + 2 = 20</span></span>
<span><span>2. </span><span> 5y = 20 – 2</span></span>
<span><span> 3. </span><span> 5y = 18</span></span>
<span><span>4. </span><span> Y = 18 / 5</span></span>
<span><span> 5. </span><span> Y = 3.6</span></span>
<span><span> 6. </span><span> 5y = 5(3.6)</span></span>
<span><span> 7. </span><span> Annie = 18</span></span>
Hence, Annie traveled 18 hours while Brian traveled 3.6
hours.
If we assume the given segments are those from the vertices to the point of intersection of the diagonals, it seems one diagonal (SW) is 20 yards long and the other (TR) is 44 yards long. The area (A) of the kite is half the product of the diagonals:
