Answer:
Explanation:
Assuming that the temperature does not change, you can use Boyle's law of ideal gases:
The data are:
- P₁ = 100atm
- V₁ = 5 ml
- P₂ = 1 atm
- V₂ = ?
Substitute, compute and find V₂:
When a light bulb is turned on, it is powered by electricity and manages to produce both light and heat. This is something as persons we know from experience. Thus when a light bulb is turned on, ELECTRICAL ENERGY IS TRANSFORMED INTO LIGHT AND HEAT ENERGY. (Option B)
If the experiment is not performed right,you can redo the experiment.
Answer:
30.34g (corrected to 4 significant figures).
Explanation:
Take the atomic mass of C=12.0, H=1.0, O=16.0.
no. of moles = mass / molar mass
So, no. of moles of butane reacted = 10 / (12x4 + 1x10)
= 0.172414 mol
Since O2 is in excess and butane is the limiting reagent, the no. of moles of carbon dioxide produced depends on the no. of moles of butane reacted.
From the equation, the mole ratio of butane:Carbon dioxide = 2: 8 = 1: 4,
meaning 1 mole of butane gives 4 moles of CO2.
Using this ratio,
we can deduce that the no. of moles of CO2 produced = 0.172414 x 4
=0.689655 mol
As mass = no. of moles x molar mass
mass of CO2 produced = 0.689655 x (12.0+16.0x2)
=30.34g (corrected to 4 significant figures).
Answer:
Peatification and coalification
Explanation:
https://energyeducation.ca/encyclopedia/Coal_formation