3 years ago

If 3 g of element C combine with 8 g of element D to form compound CD, how many grams of D are needed to form compound CD2?

1 answer:

8 0

<span>For the answer to the question above,
If 3g of element combines with 8g of D to form CD it means
1 mole of C = 3g
1 mole of D = 8g
hence it forms CD.
So to form CD2 you need 16g of element D
I hope my answer helped you</span>

You might be interested in

For the reaction 2hno3 + mg(oh)2 → mg(no3)2 + 2h2o, how many moles of magnesium nitrate are produced from 8.00 moles of nitric a

Sladkaya [172]

You would get four moles of magnesium nitrate :) you would have to
“ ?molesmg(oh)2 = 8molmg(no3)2 x molmg(oh)2 / 2molhno3 = 4 moles of magnesium nitrate :))) hopefully this helps! <3

7 0

2 years ago

H2CO3(aq) → CO2(aq) + H2O(l) After strenuous exercise, you breathe heavily, exhaling and removing CO2 from your body. The remova

Aleksandr-060686 [28]

Answer:

did you find the answer

Explanation:

help

6 0

2 years ago

A generic weak acid with formula HA has a Ka = 2.76 x 10-8. Calculate the Kb for the conjugate base of the acid.

Reika [66]

Answer:

3.62x10⁻⁷ = Kb

Explanation:

The acid equilibrium of a weak acid, HX, is:

HX + H₂O ⇄ X⁻ + H₃O⁺

Where Ka = [X⁻] [H₃O⁺] / [HX]

And basic equilibrium of the conjugate base, is:

X⁻ + H₂O ⇄ OH⁻ + HX

Where Kb = [OH⁻] [HX] / [X⁻]

To convert Ka to Kb we must use water equilibrium:

2H₂O ⇄ H₃O⁺ + OH⁻

Where Kw = 1x10⁻¹⁴ = [OH⁻] [H₃O⁺]

Thus, we can obtain:

Kw = Ka*Kb

Solving for Kb:

Kw / Ka = Kb

1x10⁻¹⁴ / 2.76x10⁻⁸ =

3.62x10⁻⁷ = Kb

4 0

3 years ago

What volume of 6.58M HCI is needed to make 500. mL of 3.00M HCI?

zmey [24]

Answer:

228 mL

Explanation:

M1*V1 = M2*V2

M1 = 6.58 M

V1 = ?

M2 = 3.00 M

V2 = 500 mL

V1 = M2*V2/M1 = 3.00M*500.mL/6.58 M = 228 mL

3 0

3 years ago

An atom has atomic number of 34. how many protons and electrons does it have? what is its symbol? 34 protons and electrons. se l

AURORKA [14]

Se: Selenium

Protons: 34
Electrons: All atoms in the periodic table are neutral until changed otherwise
Neutrons: 44
Atomic Mass: 78.09

>Symbol attached<

4 0

2 years ago