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3 years ago

During which phase change does the arrangement of water molecules become more orderly?

Chemistry

2 answers:

Murrr4er [49]3 years ago

8 0

The arrangement of water molecules become orderly during $\boxed{{\text{B}}{\text{. freezing}}}$ .

Further Explanation:

Phase transition is defined as the change from one state to another state but no change in chemical composition is observed. It is also known as a phase change, state change or physical change.

A. Melting

It is the process in which a substance transforms from its solid state to the liquid state. This is also known as fusion. The strong bonds between the solid particles get broken down to form liquid that has weaker bonds than the former state.

B. Freezing

It is a phase transition in which liquid gets converted into solid by lowering its temperature. Here, the weaker forces between liquid particles are replaced by the strong forces that occur between solid particles.

C. Boiling

It is the process that takes place when a liquid gets converted into its vapors. This is done by heating the liquid up to its boiling point. Here, the weak forces between liquid particles are replaced by the weaker forces that occur between gas particles.

D. Condensing

This process comes into account when vapors are converted into the liquid state. This is done by changing temperature and pressure of the substance. Here, the weaker forces between liquid particles are replaced by slightly stronger forces that occur between liquid particles.

Due to strong intermolecular forces, the particles are more orderly arranged in solids than any other state of matter. Since solid is formed in case of freezing. So option B is correct.

Learn more:

Identify the phase change in which crystal lattice is formed: brainly.com/question/1503216
The main purpose of conducting experiments: brainly.com/question/5096428

Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: Phase transition

Keywords: phase transition, phase change, condensing, boiling, freezing, melting, liquid, vapor, solid, temperature, pressure, state change.

KatRina [158]3 years ago

3 0

The phase change in which the water molecules become most orderly is the freezing. This is the process of changing water as liquid to its solidified form. The process of freezing is an exothermic which means that for this to occur, heat should be removed from the system.

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Andrew [12]

Given :

2NOBr(g) - -> 2NO(g) + Br2(g)

Initial pressure of NOBr , 1 atm .

At equilibrium, the partial pressure of NOBr is 0.82 atm.

To Find :

The equilibrium constant for the reaction .

Solution :

2NOBr(g) - -> 2NO(g) + Br2(g)

t=0 s 1 atm 0 0

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So ,

$1-2x=0.82\\\\x=0.09$

At equilibrium :

$K_{eq}=\dfrac{[NO]^2[br_2]}{[NOBr]^2}\\\\K_{eq}=\dfrac{0.18^2\times 0.9}{0.82^2}\\\\K_{eq}=0.043\ atm$

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3 years ago

Limes and lemons have a ph of 2 and are _____. acidic basic bases hydroxides

alexdok [17]

Limes and lemons have a ph of 2 and are acidic.

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3 years ago

A reaction was suppose to produce 20 L of gas. Only 12 litters of gas were produced in the lab. What is the percent yield for th

pogonyaev

Answer:

$\boxed {\boxed {\sf 60 \%}}$

Explanation:

Percent yield is a ratio of the actual yield to the theoretical yield. It is found using this formula:

$\% \ yield= \frac {actual \ yield}{theoretical \ yield} *100$

The actual yield is 12 liters, because that was actually produced in the lab.

The theoretical yield is 20 liters, because that was the expected yield.

$\% \ yield= \frac {12 \ L}{20\ L} *100$

$\% \ yield= 0.6*100$

$\% \ yield= 60$

For this reaction, the percent yield is 60%.

5 0

2 years ago

When 5.00 g of Al2S3 and 2.50 g of H2O are reacted according to the following reaction: Al2S3(s) + 6 H2O(l) → 2 Al(OH)3(s) + 3 H

Debora [2.8K]

Answer:

$Y=58.15\%$

Explanation:

Hello,

For the given chemical reaction:

$Al_2S_3(s) + 6 H_2O(l) \rightarrow 2 Al(OH)_3(s) + 3 H_2S(g)$

We first must identify the limiting reactant by computing the reacting moles of Al2S3:

$n_{Al_2S_3}=5.00gAl_2S_3*\frac{1molAl_2S_3}{150.158 gAl_2S_3} =0.0333molAl_2S_3$

Next, we compute the moles of Al2S3 that are consumed by 2.50 of H2O via the 1:6 mole ratio between them:

$n_{Al_2S_3}^{consumed}=2.50gH_2O*\frac{1molH_2O}{18gH_2O}*\frac{1molAl_2S_3}{6molH_2O}=0.0231mol Al_2S_3$

Thus, we notice that there are more available Al2S3 than consumed, for that reason it is in excess and water is the limiting, therefore, we can compute the theoretical yield of Al(OH)3 via the 2:1 molar ratio between it and Al2S3 with the limiting amount:

$m_{Al(OH)_3}=0.0231molAl_2S_3*\frac{2molAl(OH)_3}{1molAl_2S_3}*\frac{78gAl(OH)_3}{1molAl(OH)_3} =3.61gAl(OH)_3$

Finally, we compute the percent yield with the obtained 2.10 g:

$Y=\frac{2.10g}{3.61g} *100\%\\\\Y=58.15\%$

Best regards.

7 0

2 years ago

The molarity of an aqueous sodium phosphate solution is 0.650 M. What is the molality of sodium ions present in this solution? T

netineya [11]

Answer:

molality of sodium ions is 1.473 m

Explanation:

Molarity is moles of solute per litre of solution

Molality is moles of solute per kg of solvent.

The volume of solution = 1 L

The mass of solution = volume X density = 1000mL X 1.43 = 1430 grams

The mass of solute = moles X molar mass of sodium phosphate = 0.65X164

mass of solute = 106.6 grams

the mass of solvent = 1430 - 106.6 = 1323.4 grams = 1.3234 Kg

the molality = $\frac{moles of solute}{mass of solvent in kg}=\frac{0.65}{1.323}= 0.491m$

Thus molality of sodium phosphate is 0.491 m

Each sodium phosphate of molecule will give three sodium ions.

Thus molality of sodium ions = 3 X 0.491 = 1.473 m

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3 years ago