13 half-lives have passed
<h3>Further explanation
</h3>
General formulas used in decay:
T = duration of decay
t 1/2 = half-life
N₀ = the number of initial radioactive atoms
Nt = the number of radioactive atoms left after decaying during T time
t1/2 = 4 days
Nt=18 mg (0.01% of the original isotope)
18 mg (Nt) = 0.01% No
No = the original isotope :
The duration of decay (T) :
Half-lives passed :
Answer:
The correct answer is: alcohol (C-OH) functional group
Explanation:
Electronegativity is described as the ability or the tendency of an element to attract the electron density or shared bonding electrons towards itself.
The electronegativity value of oxygen atom, nitrogen atom and, carbon atom is 3.44, 3.04, and 2.55.
From this data we can conclude that oxygen is more electronegative than nitrogen. Also, the electronegativity difference of oxygen and carbon (0.89) is greater than the electronegativity difference of nitrogen and carbon (0.49).
Therefore, <u>the</u><u> electronegativity </u><u>of the oxygen containing </u><u>alcohol</u><u> functional group (C-OH) will be greater than the electronegativity of the nitrogen (C-NH) containing amine functional group.</u>
Answer:
Molecular Formula = N₃P₃Cl₆
Explanation:
Molecular formula is calculated by using following formula,
Molecular Formula = n × Empirical Formula ---- (1)
Also, n is given as,
n = Molecular Weight / Empirical Formula Weight
Molecular Weight = 347.64 g.mol⁻¹
Empirical Formula Weight = 1 (N) + 1 (P) + 2 (Cl) = 115.88 g.mol⁻¹
So,
n = 347.64 g.mol⁻¹ ÷ 115.88 g.mol⁻¹
n = 3
Putting Empirical Formula and value of "n" in equation 1,
Molecular Formula = 3 × NPCl₂
Molecular Formula = N₃P₃Cl₆
The answer is 28% as u find the molar mass of cu and divide it by the total molar mass
You add the protons of each atom together. The fact that it is an ionic compound shouldn't bother you at all.