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Ksenya-84 [330]
3 years ago
7

Dot and cross diagram for oxygen ion

Chemistry
1 answer:
KatRina [158]3 years ago
4 0

Answer:

Explanation:

We can use dot and cross diagrams to show how a pair of electrons forms a covalent bond.

Here is the dot and cross diagram for oxygen (O2), a diatomic molecule. Notice the lone pairs of electrons and the two shared pairs of electrons.

There are different kinds of covalent bonds:

a single covalent bond is when two atoms share a single pair of electrons. Represented by a single line (–).

a double covalent bond is when two atoms share two pairs of electrons. Represented by a double line (=).

a triple covalent bond is when two atoms share three pairs of electrons. Represented by a triple line (≡).

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One mole of oxygen gas is at a pressure of 6.00 atm and a temperature of 27.0°C. (a) If the gas is heated at constant volume unt
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V= Volume of the gas = ?

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V=\frac{nRT}{P}=\frac{1\times 0.0821\times 300}{6.00}=4.10L

a) To calculate the final temperature of the system, we use the equation given by Gay-Lussac Law. This law states that pressure of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

\frac{P_1}{T_1}=\frac{P_2}{T_2}

where,

P_1\text{ and }T_1 are the initial pressure and temperature of the gas.

P_2\text{ and }T_2 are the final pressure and temperature of the gas.

We are given:

P_1=6.00atm\\T_1=300K\\P_2=3\times 6.00=18.0atm\\T_2=?

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\frac{6.00}{300K}=\frac{18.0}{T_2}\\\\T_2=900K

The final temperature is 900 K

b) The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas = 6.00 atm

P_2 = final pressure of gas = 2\times 6.00atm=12.0atm

V_1 = initial volume of gas = 4.10 L

V_2 = final volume of gas =  2\times 4.10 L=8.20L

T_1 = initial temperature of gas = 300K

T_2 = final temperature of gas =?

Now put all the given values in the above equation, we get:

\frac{6.00\times 4.10}{300}=\frac{12.0\times 8.20}{T_2}

T_2=1200K

The final temperature is 1200 K

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