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3 years ago

Dot and cross diagram for oxygen ion

Chemistry

1 answer:

KatRina [158]3 years ago

4 0

Answer:

Explanation:

We can use dot and cross diagrams to show how a pair of electrons forms a covalent bond.

Here is the dot and cross diagram for oxygen (O2), a diatomic molecule. Notice the lone pairs of electrons and the two shared pairs of electrons.

There are different kinds of covalent bonds:

a single covalent bond is when two atoms share a single pair of electrons. Represented by a single line (–).

a double covalent bond is when two atoms share two pairs of electrons. Represented by a double line (＝).

a triple covalent bond is when two atoms share three pairs of electrons. Represented by a triple line (≡).

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Which of the following would be more likely to conduct electrons? Strontium or Iodine? Defend your choice.

Alchen [17]

Strontium because it is a metal

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3 years ago

Quis critérios foram usadps por dobereiner em sua tentava de organiza os elementos químicos?

anyanavicka [17]

Döbereiner grouped the known elements into triads (sets of three) so that

• The atomic mass of the middle element was approximately the average of the other two

• The chemical properties of the middle element were between those of the other two

• The physical properties of the middle element were between those of the other two

One example of a triad is Li – Na – K.

(a) Atomic mass of Na = 23.0 u

Average atomic mass of Li and K = (6.9 u + 39.1 u)/2 = 46.0 u/2 = 23.0 u

(b) Li reacts slowly with water. Na reacts rapidly. Potassium reacts violently.

Average melting point of Li and K = (454 °C + 330 °C)/2 = 784 °C/2

= 392 °C

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2 years ago

Give three examples of heterogeneous mixtures and three examples of solutions that you might use in everyday life.

beks73 [17]

Answer:

Explanation:

Heterogeneous mixtures: Milk, salt and pepper, smog, chocolate chip cookie, oil and water.

Solutions we might use everyday: Gatorade, Apple Juice, most wines and liquor, liquid detergent, coffee etc.

7 0

3 years ago

What are the empirical and molecular formulas of a hydrocarbon if combustion of 2.10 g of the compound yields 6.59 g co2 and 2.7

mariarad [96]

The empirical formula of hydrocarbon is CH2

The molecular formula of the hydrocarbon is C6H12

Explanation

Hydrocarbon is made up of carbon and hydrogen

<h3> Empirical formula calculation</h3>

Step 1: find the moles CO2 and H2O

moles =mass/molar mass

moles of CO2 = 6.59 g/ 44 g/mol = 0.15 moles

moles of H2O = 2.70 g / 18 g/mol = 0.15 moles

Step 2: Find the moles ratio of Co2:H2O by diving each mole by smallest mole(0.15)

that is for CO2 = 0.15/0.15 =1

For H2O = 0.15/0.15 =1

therefore the mole ratio of Co2 : H2O = 1:1 which implies that 1 mole of Co2 and 1 mole of H2O is formed during combustion reaction.

From the the law of mass conservation the number of atoms in reactant side must be equal to number of atoms in product side

therefore since there 1 atom of C in product side there must be 1 atom of C in reactant side.

In addition there is 2 H atom in product side which should be the same in reactant side.

From information above the empirical formula is therefore = CH2

Molecular formula calculation

[CH2}n= 84 g/mol

[12+ (1x2)] n = 84 g/mol

14 n = 84 g/mol

n = 6

multiply the each subscript in CH2 by 6

Therefore the molecular formula = C6H12

5 0

3 years ago

Calculate the mass (in grams) of 250mL of ether at 25 oC. The density of

leonid [27]

Volume=250mL
Density=0.71g/ml

$\boxed{\sf Density=\dfrac{Mass}{Volume}}$

$\\ \sf{:}\implies Mass=Density(Volume)$

$\\ \sf{:}\implies Mass=0.71(250)$

$\\ \sf{:}\implies Mass=177.5g$

6 0

2 years ago