Given that
log (x+y)/5 =( 1/2) {log x+logy}
We know that
log a+ log b = log ab
⇛log (x+y)/5 =( 1/2) log(xy)
We know that log a^m = m log a
⇛log (x+y)/5 = log (xy)^1/2
⇛log (x+y)/5 = log√(xy)
⇛(x+y)/5 = √(xy)
On squaring both sides then
⇛{ (x+y)/5}^2 = {√(xy)}^2
⇛(x+y)^2/5^2 = xy
⇛(x^2+y^2+2xy)/25 = xy
⇛x^2+y^2+2xy = 25xy
⇛x^2+y^2 = 25xy-2xy
⇛x^2+y^2 = 23xy
⇛( x^2+y^2)/xy = 23
⇛(x^2/xy) +(y^2/xy) = 23
⇛{(x×x)/xy} +{(y×y)/xy} = 23
⇛(x/y)+(y/x) = 23
Therefore, (x/y)+(y/x) = 23
Hence, the value of (x/y)+(y/x) is 23.
Lucy would save $114.
Step 1: Multiply 6.175 x 30 = 185.25
Step 2: Divide 370,000/185.25 = 1,997
Step 3: Repeat Steps 1&2 but with (6.55 x 30) and divide 370,000/196.5 = 1,883.
Step 4: Subtract 1,997 - 1,883 = 114
Step 5: She will save $114 with points versus without.
9514 1404 393
Answer:
see below
Step-by-step explanation:
You might do well to refer to the proof referenced here--the previous slide. We assume it more or less matches what we've done in the attachment.
X<4 hope this helped dude
