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dalvyx [7]
3 years ago
14

Gas A has molecules with small mass. Gas B has molecules with larger mass. They are at the same temperature.

Physics
1 answer:
Julli [10]3 years ago
6 0

Answer:

c)The gases have the same average kinetic energy.

Explanation:

As we know that the kinetic energy of gas is given as

K = \frac{1}{2}mv^2

here we know that

v = \sqrt{\frac{3RT}{M}}

so we have

K = \frac{1}{2}m (\frac{3RT}{M})

now we have

K = \frac{3}{2}n RT

now mean kinetic energy per molecule is given as

K_{avg} = \frac{3}{2}KT

so this is independent of the mass of the gas

so average kinetic energy will remain same for both the gas molecules

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If one oscillation has 5. 8 times the energy of a second one of equal frequency and mass, what is the ratio of their amplitudes?
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The ratio of their amplitudes will be 2.41.

To find the answer, we have to know more about the simple harmonic motion.

<h3>How to find the ratio of their amplitudes?</h3>
  • It is given that,

                        E_1=5.8E_2\\m_1=m_2 \\\omega_1=\omega_2

  • We have the relation between these quantities and amplitudes as,

                        A=\sqrt\frac{2E}{k} \\k=m\omega^2

  • Here, for both the oscillation, k will be same.
  • Thus, the ratio of amplitude will be,

                      \frac{A_1}{A_2} =\sqrt{\frac{E_1}{E_2} } =\sqrt{\frac{5.8E_2}{E_2} } =2.41

Thus, we can conclude that, the ratio of their amplitudes will be 2.41.

Learn more about simple harmonic motion here:

brainly.com/question/22422926

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