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3 years ago

The mercalli scale is a scale from ________.

Physics

1 answer:

Mashcka [7]3 years ago

6 0

<h2>Answer: 1 to 12. </h2>

The Mercalli seismological scale is a scale of 12 degrees, where 1 is very weak and 12 catastrophic.

This scale owes its name to the Italian physicist Giuseppe Mercalli and was developed to assess the intensity of earthquakes through the effects and damages caused to different structures.

This means the Mercalli scale measures how strong a earthquake has been by its consequences and not by its magnitude, therefore it is based on empirical observations.

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A bicycle rider has a speed of 20.0 m/s at a height of 60 m above sea level when he begins coasting down hill. Sea level is the

IRINA_888 [86]

Answer:

The rider's speed will be approximately 35 m/s

Explanation:

Initially the rider has kinetic and potential energy, and after going down the hill, some of the potencial energy turns into kinetic energy. So using the conservation of energy, we have that:

$kinetic_1 + potencial_1 = kinetic_2 + potencial_2$

The kinetic and potencial energy are given by:

$kinetic = mass * speed^2 / 2$

$potencial = mass * gravity * height$

So we have that:

$m*v^2/2 + mgh = m*v'^2/2 + mgh'$

$20^2/2 + 9.81*60 = v'^2/2 + 9.81*18$

$v'^2/2 + 176.58 = 788.6$

$v'^2/2 = 612.02$

$v'^2 = 1224.04$

$v' = 34.99\ m/s$

So the rider's speed will be approximately 35 m/s

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3 years ago

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3 years ago

Read 2 more answers

What is the speed of a cyclist that rides west 88 km in 32 minutes?

suter [353]

Answer:

The speed of the cyclist is 2.75 km/min.

Explanation:

Given

The distance d = 88 km

Time t = 32 minutes

To determine

We need to find the speed of a cyclist.

In order to determine the speed of a cyclist, all we need to do is to divide the distance covered by a cyclist by the time taken to cover the distance.

Using the formula involving speed, time, and distance

$s=\frac{d}{t}$

where

s = speed

d = distance covered

t = time taken

substitute d = 88, and t = 32 in the formula

$s=\frac{d}{t}$

$s=\frac{88}{32}$

Cancel the common factor 8

$s=\frac{11}{4}$

$s=2.75$ km/min

Therefore, the speed of the cyclist is 2.75 km/min.

8 0

3 years ago

A crate is dragged up a ramp at constant speed. The work done on the system can be accounted for by:

Alex

Answer:

The work done on the system can be accounted for by;

Both $E_g$ and $E_{int}$

Explanation:

The speed of the crate = Constant

Therefore, the acceleration of the crate = 0 m/s²

The net force applied to the crate, $F_{NET}$ = 0

Therefore, the force of with which the crate is pulled = The force resisting the upward motion of the crate

However, we have;

The force resisting the upward motion of the crate = The weight of the crate + The frictional resistance of the ramp due to the surface contact between the ramp and the crate

The work done on the system = The energy to balance the resisting force = The weight of the crate × The height the crate is raised + The heat generated as internal energy to the system

The weight of the crate × The height the crate is raised = Gravitational Potential Energy = $E_g$

The heat generated as internal energy to the system = $E_{int}$

Therefore;

The work done on the system = $E_g$ + $E_{int}$ .

6 0

3 years ago

A 1423-kg car is moving along a level highway with a speed of 26.4 m/s. The driver takes the foot off the accelerator and the ca

Leona [35]

Answer:

Final speed, v = 28.81 m/s

Explanation:

Given that,