Ask question

Ask question

All categories

3 years ago

14

The mercalli scale is a scale from ________.

1 answer:

Mashcka [7]3 years ago

6 0

<h2>Answer: 1 to 12. </h2>

<u>The Mercalli seismological scale is a scale of 12 degrees</u>, where 1 is very weak and 12 catastrophic.

This scale owes its name to the Italian physicist Giuseppe Mercalli and was developed to assess the intensity of earthquakes through the effects and damages caused to different structures.

This means the <u>Mercalli scale measures how strong a earthquake has been by </u><u>its consequences and not by its magnitude</u><u>, therefore it is based on </u><u>empirical observations.</u>

You might be interested in

The two main currents that affect the united states on the eat coast and west coast

Virty [35]

<span>The California current on the west coast which runs from north to south and the Gulf Stream on the East coast which runs from south to north.</span>

3 0

3 years ago

Read 2 more answers

Interactive Solution 28.5 illustrates one way to model this problem. A 7.11-kg object oscillates back and forth at the end of a

____ [38]

Explanation:

Given that,

Mass of the object, m = 7.11 kg

Spring constant of the spring, k = 61.6 N/m

Speed of the observer, $v=2.79\times 10^8\ m/s$

We need to find the time period of oscillation observed by the observed. The time period of oscillation is given by :

$t_o=2\pi \sqrt{\dfrac{m}{k}} \\\\t_o=2\pi \sqrt{\dfrac{7.11}{61.6}} \\\\t_o=2.13\ s$

Time period of oscillation measured by the observer is :

$t=\dfrac{t_o}{\sqrt{1-\dfrac{v^2}{c^2}} }\\\\t=\dfrac{2.13}{\sqrt{1-\dfrac{(2.79\times 10^8)^2}{(3\times 10^8)^2}} }\\\\t=5.79\ s$

So, the time period of oscillation measured by the observer is 5.79 seconds.

3 0

3 years ago

A tennis ball of mass 0.060 kg travels horizontally at a speed of 25m/s. The ball hits a tennis

stepladder [879]

It would be A because a is perfect

7 0

3 years ago

Read 2 more answers

What is the total wavelength if one-half of the wave is 3?

seraphim [82]

Answer:

6

Explanation:

Half the wave = 3

Wavelength = 3 x 2 = 6

3 0

2 years ago

A mass m is attached to an ideal massless spring. When this system is set in motion with amplitude a, it has a period t. What is

Luden [163]

The period will be the same if the amplitude of the motion is increased to 2a

What is an Amplitude?

Amplitude refers to the maximum extent of a vibration or oscillation, measured from the position of equilibrium.

Here,

mass m is attached to the spring.

mass attached = m

time period = t

We know that,

The time period for the spring is calculated with the equation:

$T = 2\pi \sqrt{\frac{m}{k} }$

Where k is the spring constant

Now if the amplitude is doubled, it means that the distance from the equilibrium position to the displacement is doubled.

From the equation, we can say,

Time period of the spring is independent of the amplitude.

Hence,

Increasing the amplitude does not affect the period of the mass and spring system.

Learn more about time period here:

<u>brainly.com/question/13834772</u>

#SPJ4

7 0

2 years ago