Second and third class levers both have __________.
2 answers:
The answer would be:
<u><em>D. the fulcrum at one end of the lever.</em></u>
Both second class and third class levers have their fulcrum located at the end of the lever. They differ in the location of the load and effort. For third class levers the effort is in between the load and the fulcrum. For second class levers, the load is in between the effort and fulcrum. You can look at the attached picture as reference.
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Answer:
You need to use the equations of motion which I wrote down in the image. Since the runner starts from rest, the initial velocity(v0) is 0 and initial position(x0) is also 0. The solution is in the image attached below.
Answer:
a) # buses = 7
Explanation:
For this exercise we use the kinematic equations, let's find the time it takes to reach the same height
y = t - ½ g t²
Let's decompose the speed, with trigonometry
v₀ₓ = v₀ cos θ
= v₀ sin θ
v₀ₓ = 40 cos 32
v₀ₓ = 33.9 m / s
= 40 sin32
= 21.2 m / s
When it arrives it is at the same initial height y = 0
0 = ( - ½ gt) t
That has two solutions
t = 0 when it comes out
t = 2 / g when it arrives
t = 2 21.2 /9.8
t = 4,326 s
We use the horizontal displacement equation
x = vox t
x = 33.9 4.326
x = 146.7 m
To find the number of buses we can use a direct proportions rule
# buses = 146.7 / 20
# buses = 7.3
# buses = 7
The distance of the seven buses is
L = 20 * 7 = 140 m
b) let's look for the scope for this jump
R = vo2 sin2T / g
R = 40 2 without 2 32 /9.8
R = 146.7 m
As we can see the range and distance needed to pass the seven (7) buses is different there is a margin of error of 6.7 m in favor of the jumper (security)