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garik1379 [7]
3 years ago
7

Second and third class levers both have __________.

Physics
2 answers:
Zolol [24]3 years ago
5 0

Answer:

i think its d on edgenuity

Explanation:

nataly862011 [7]3 years ago
4 0

The answer would be:

<u><em>D. the fulcrum at one end of the lever.</em></u>

Both second class and third class levers have their fulcrum located at the end of the lever. They differ in the location of the load and effort. For third class levers the effort is in between the load and the fulcrum. For second class levers, the load is in between the effort and fulcrum. You can look at the attached picture as reference.

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Replacement teeth were made even back then out of primitive materials, and pig hair was used like floss
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4 years ago
An elevator whose mass is m = 400 kilograms is supported by a cable. A frictional force of f = 80 newtons is applied to the elev
Dmitry_Shevchenko [17]

Answer:

3924 N

5124 N

4004 N

2884 N

4004 N

Explanation:

m = Mass of elevator = 400 kg

g = Acceleration due to gravity = 9.81 m/s²

a = Acceleration

f = Friction force = 80 N

When the elevator is stationary only the acceleration due to gravity will be acting on it

Tension

T=mg\\\Rightarrow T=400\times 9.81\\\Rightarrow T=3924\ N

The tension is 3924 N

The balanced force equation would be

T-mg-f=ma\\\Rightarrow T=ma+mg+f\\\Rightarrow T=400\times 2.8+400\times 9.81+80\\\Rightarrow T=5124\ N

The tension is 5124 N

When velocity is constant acceleration is zero

T-mg-f=0\\\Rightarrow T=mg+f\\\Rightarrow T=400\times 9.81+80\\\Rightarrow T=4004\ N

The tension is 4004 N

T-mg-f=-ma\\\Rightarrow T=-ma+mg+f\\\Rightarrow T=-400\times 2.8+400\times 9.81+80\\\Rightarrow T=2884\ N

The tension would be 2884 N

When velocity is constant acceleration is zero

T-mg-f=0\\\Rightarrow T=mg+f\\\Rightarrow T=400\times 9.81+80\\\Rightarrow T=4004\ N

The tension is 4004 N

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4 years ago
How does the scientific process generally begin?
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There are several approaches. The most favourable one (in my opinion) is this one:
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3. Creating a hypothesis (NOT a thesis!)
4. Experimenting (to prove the hypothesis)
5. Analysing results from the experiment
6. Writing a thesis
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4 years ago
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A 15-uF capacitor is connected to a 50-V battery and becomes fullycharged. The battery is
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A. C = 75μF and B. V = 10V.

We have to use the equation k = C/C₀ and k = V₀/V which both are the dielectric constant.

A. The capacitance after the slab is inserted.

With C₀ = 15μF and k = 5.0. Clear k for the equation k = C/C₀:

C = k*C₀

C = (5.0)(15x10⁻⁶F) = 0.000075F

C = 75μF

B. The voltage across the capacitor's plates after the slab is inserted.

With V₀ = 50V and k = 5.0. Clear V from the equation k = V₀/V:

V = V₀/k

V = 50V/5.0

V = 10V

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3 years ago
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