A section of uniform pipe is bent into an upright U shape and partially filled with water, which can then oscillate back and for
th in simple harmonic motion. The inner radius of the pipe is r = 0.011 m. The radius of curvature of the curved part of the U is R = 0.15 m. When the water is not oscillating, the depth of the water in the straight sections is d = 0.21 m.
Write an expression for the mass of water in the tube, in terms of the defined quantities and the density of water, rho. Use the approximation r«R.
Write an expression for the mass of water in the tube, in terms of the defined quantities and the density of water, rho. Use the approximation r«R.
1 answer:
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Answer:
The capillary rise of the glycerin is most nearly
Explanation:
From the question we are told that
The diameter of the glass tube is
The density of glycerin is
The surface tension of the glycerin is
The capillary rise of the glycerin is mathematically represented as
substituting value
Therefore the height of the glass tube the glycerin was able to cover is
Answer:
1000 N
Explanation:
First, we need to find the deceleration of the running back, which is given by:
where
v = 0 is his final velocity
u = 5 m/s is his initial velocity
t = 0.5 s is the time taken
Substituting, we have
And now we can calculate the force exerted on the running back, by using Newton's second law:
so, the magnitude of the force is 1000 N.