A section of uniform pipe is bent into an upright U shape and partially filled with water, which can then oscillate back and for
th in simple harmonic motion. The inner radius of the pipe is r = 0.011 m. The radius of curvature of the curved part of the U is R = 0.15 m. When the water is not oscillating, the depth of the water in the straight sections is d = 0.21 m.
Write an expression for the mass of water in the tube, in terms of the defined quantities and the density of water, rho. Use the approximation r«R.
Write an expression for the mass of water in the tube, in terms of the defined quantities and the density of water, rho. Use the approximation r«R.
1 answer:
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Answer:
Explanation:
Total length of the wire is 29 m.
Let the length of one piece is d and of another piece is 29 - d.
Let d is used to make a square.
And 29 - d is used to make an equilateral triangle.
(a)
Area of square = d²
Area of equilateral triangle = √3(29 - d)²/4
Total area,
Differentiate both sides with respect to d.
For maxima and minima, dA/dt = 0
d = 8.76 m
Differentiate again we get the
(a) So, the area is maximum when the side of square is 29 m
(b) so, the area is minimum when the side of square is 8.76 m