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Tomtit [17]
3 years ago
7

A section of uniform pipe is bent into an upright U shape and partially filled with water, which can then oscillate back and for

th in simple harmonic motion. The inner radius of the pipe is r = 0.011 m. The radius of curvature of the curved part of the U is R = 0.15 m. When the water is not oscillating, the depth of the water in the straight sections is d = 0.21 m.
Write an expression for the mass of water in the tube, in terms of the defined quantities and the density of water, rho. Use the approximation r«R.

Physics
1 answer:
nadezda [96]3 years ago
7 0

Answer:

The expression is shown in the picture below

Explanation:

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two billiard balls moving along the same line hit each other head-on. each has a mass of 0.220 kg; one has an initial velocity o
Tems11 [23]

Hi there!

Since the collision is elastic, we must also satisfy the following condition:

Ei = Ef, or:

KEi = KEf

Begin by writing an expression for momentum. (p = mv) Remember that one ball's direction is negative; in this instance, we can let the second ball be moving LEFT.

mv1 + mv2 = mvf1 + mvf2

0.220(1.84) + 0.220(-.530) = 0.220(vf1 + vf2)

0.2882/0.220 = vf1 + vf2

1.31 = vf1 + vf2

Now, we can express this as a conservation of energy:

1/2mv1² + 1/2mv2² = 1/2mvf1² + 1/2mvf2²

Plug in values and simplify:

0.403315 = 1/2m(vf1² + vf2²)

Simplify further:

3.6665 = vf1² + vf2²

Use the equation derived from momentum above and solve for one variable:

vf2 = 1.31 - vf1

Plug in this expression for vf2:

3.6665 = vf1² + (1.31 - vf1)²

Expand:

3.6665 = vf1² + 1.7161 - 2.62vf1 + vf1²

Simplify:

1.9504 = -2.62vf1 + 2vf1²

Solve for vf1 using a graphing calculator:

vf1 = -0.53 m/s or 1.84 m/s; we must figure out which one is correct.

Since v1 is heading to the right initially with a velocity of 1.84 m/s, we know that the ball's velocity could not have stayed the same in both magnitude and direction, so the final velocity must be -0.53 m/s.

Now, we can solve for the velocity of the other ball (initial of 0.53 m/s):

vf2 = 1.31 - (-0.53) = 1.84 m/s.

Now, you could have also made the connection that when two balls of the SAME MASS experience an ELASTIC collision, the velocities are simply "exchanged" from one to another. I just used this more "extensive" method to prove this.

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3 years ago
What is the mass, in grams, of 2.00 moles of H2O?
tia_tia [17]

Answer:

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Explanation:

Given parameters:

Number of moles of H₂O = 2moles

Unknown:

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Solution:

To solve this problem, use the expression below:

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3 0
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