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kumpel [21]
3 years ago
8

A 25.00 ml sample of h3po4 solution is neutralized by exactly 54.93 ml of 0.04345 m ca(oh)2. what is the molarity of the h3po4 s

olution?

Chemistry
2 answers:
son4ous [18]3 years ago
8 0
The neutralization equation is:
3 Ca(OH)₂ + 2 H₃PO₄ → Ca₃(PO₄)₂ + 6 H₂O

From this equation we can see that 3 moles of Ca(OH)₂ react with 2 moles of H₃PO₄

Numbers of mmol of Ca(OH)₂ = M x V = 0.04345 x 54.93 = 2.387 mmol

Number of mmol of H₃PO₄ = 2.387 x (2/3) = 1.591 mmol

Molarity of solution = n (mmol) / V(ml) = 1.591 / 25 = 0.0636 M
Anestetic [448]3 years ago
6 0

<em>With an acid-base titration formula, The molarity of the H₃PO4₄ solution = 0.06372 M </em>

<h3><em>Further explanation </em></h3>

Titration is a procedure for determining the concentration of a solution by reacting with another solution which is known to be concentrated (usually a standard solution). Determination of the endpoint/equivalence point of the reaction can use indicators according to the appropriate pH range

Titrations can be distinguished including acid-base titration, depositional titration, and redox titration. An acid-base titration is the principle of neutralization of acids and bases is used.

An acid-base titration there will be a change in the pH of the solution. When the acid is alkaline the pH drops, and vice versa if the acid is alkaline then the pH will rise.

From this pH change a Titration Curve can be made which is a function of acid / base volume and pH of the solution

Acid-base titration formula

\large{\boxed{\bold{Ma~Va~na~=~Mb~Vb~nb}}}

Ma, Mb = acid base concentration

Va, Vb = acid base volume

na, nb = acid base valence

<em>Known variable </em>

A 25.00 ml sample of H₃PO₄ 54.93 ml of 0.04345 m Ca(OH)₂.

<em>Asked </em>

The molarity of the H₃PO₄ solution

<em>Answer </em>

H₃PO₄ is a weak acid with valence 3 because it releases 3 H⁺ atoms

H₃PO₄ -> 3H + + PO₄⁻

Ca(OH)₂ is a strong base with valence 2 because it releases 2OH⁻ ions

Ca(OH)₂ ---> Ca₂ + + 2OH-

We enter the numbers into the formula:

M₁.V₁.n₁= M₂.V2₂.n₂

1 = H₃PO4₄

2 = Ca(OH)₂

M1.25 ml .3 = 0.0435. 54.93 ml.2

M1 = 0.06372

So the molarity of the H₃PO4₄ solution = 0.06372 M

<h3><em>Learn more </em></h3>

the best tool to find the volume of that she needs to neutralize the acid

brainly.com/question/1538449

Determine the endpoint of the titration.

brainly.com/question/11855003

acid-base

brainly.com/question/2860255

Identify the acids and the bases

brainly.com/question/12308171

endpoint titration

brainly.com/question/1306155

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