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sammy [17]
3 years ago
6

If an unbalanced force is applied to an object what my happen to the object

Chemistry
1 answer:
Kitty [74]3 years ago
5 0

Answer:

it falls

Explanation:

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Calculate the volume of one mole of a gas at 1.00 atm pressure and 0 °C.
N76 [4]

Answer:

Solution:-

The gas is in the standard temperature and pressure condition i.e. at S.T.P

Therefore,

V

i

​

=22.4dm

3

V

f

​

=?

As given that the expansion is isothermal and reversible

∴ΔU=0

Now from first law of thermodynamics,

ΔU=q+w

∵ΔU=0

∴q=–w

Given that the heat is absorbed.

∴q=1000cal

⇒w=−q=−1000cal

Now,

Work done in a reversible isothermal expansion is given by-

w=−nRTln(

V

i

​

V

f

​

​

)

Given:-

T=0℃=273K

n=1 mol

∴1000=−nRTln(

V

i

​

V

f

​

​

)

⇒1000=−1×2.303×2×273×log(

22.4

V

f

​

​

)

Explanation:

6 0
3 years ago
What phase of matter changes volume when moved from one container to another ?
Sever21 [200]

Answer:

gas

Explanation:

6 0
3 years ago
Read 2 more answers
Which statement explains the similarity between momentum and kinetic energy of an object?
pashok25 [27]
Momentum and Kinetic Energy...They both are directly proportional to the Mass and Velocity of the object and they are the only factors which determine them.

Hope this helps!

5 0
3 years ago
Read 2 more answers
How many kg of carbon dioxide are used per year to produce their arm and hammer baking soda?
cestrela7 [59]
The complete question would be as follows:

700,000 tons of baking soda are produced per year. <span>How many kilograms of carbon dioxide are used per year to produce baking soda?

We calculate as follows:

</span><span>CO2(g) + NH3(aq) + NaCl(aq) + H2O -----> NaHCO3(s) + NH4Cl(aq)
</span>
700000 tons NaHCO3 ( 907.185 kg / 1 ton ) (<span>1 kmole NaHCO3 / 84.0 kg NaHCO3) x (1 kmole CO2 / 1 kmole NaHCO3) x (44.0 kg CO2 / 1 kmole) = 3x10^8 kg CO2

Hope this answers the question. Have a nice day.</span>
3 0
3 years ago
Plz help i need the answer ASAP If 6.20 cm3 of a 6.75 M (M = mol/dm3) solution are diluted to 85.6 cm3 with water, what is the c
Brilliant_brown [7]

Answer:

Option A. 6.75 (6.20/85.6)

Explanation:

The following data were obtained from the question:

Initial volume (V1) = 6.2cm³

Initial concentration (C1) = 6.75M

Final volume (V2) = 85.6cm³

Final concentration (C2) =.?

The final concentration can be obtained by using the dilution formula as show below:

C1V1 = C2V2

6.75 x 6.2 = C2 x 85.6

Divide both side by 85.6

C2 = (6.75 x 6.2) /85.6

C2 = 6.75 (6.2 / 85.6).

6 0
3 years ago
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