I think it might be a refracting telescope, but I do know it is between refracting telescope and reflecting telescope
First step is to balance the amount of atoms on each side
So for example if my equation that I have to balance is : Br2 -> Br-
First thing I would have to do would be :
Br2 -> 2Br-
Then I would have to balance the charges on both sides. So because there is a -2 charge on the right side I will have to add a -2 charge onto the right side as well. I would do this by :
Br2 + 2e- -> 2Br-
And now you can see the amount of atoms and the charges are balanced... So your overall reaction is now balanced too.
Answer:
Ionic solid
Explanation:
Ionic solids -
These are the type of solids , which is composed of ions , which are bond by very strong electrostatic force of attraction , are referred to as ionic solids.
And due to very strong force of attraction between the ions , they generally have very high melting point.
When the solid is dissolved in water , the ions gets separate out , and these free ions are capable to conduct electricity , and hence they are very good conductor in molten form , and are insulator in solid form.
Hence , from the given information of the question ,
The correct term is ionic solids.
Answer:
1, 2, and 3 are true.
Explanation:
The Henderson-Hasselbalch equation is:
pH = pka + log₁₀ ![\frac{[A^-]}{[HA]}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BA%5E-%5D%7D%7B%5BHA%5D%7D)
- If the pH of the solution is known as is the pKa for the acid, the ratio of conjugate base to acid can be determined. <em>TRUE</em>
pH = pka + log₁₀
If you know pH and pka:
10^(pH-pka) =
The ratio will be: 10^(pH-pka)
- At pH = pKa for an acid, [conjugate base] = [acid] in solution. <em>TRUE</em>
pH = pka + log₁₀
0 = log₁₀
10^0 =
1 =
As ratio is 1, [conjugate base] = [acid] in solution.
- At pH >> pKa for an acid, the acid will be mostly ionized. <em>TRUE</em>
pH = pka + log₁₀
If pH >> pKa, 10^(pH-pka) will be >> 1, that means that you have more [A⁻] than [HA]
- At pH << pKa for an acid, the acid will be mostly ionized. <em>FALSE</em>
pH = pka + log₁₀
If pH << pKa, 10^(pH-pka) will be << 1, that means that you have more [HA] than [A⁻]
I hope it helps!
Answer:
<h2>It makes the current viable enough to pass through an exterior wire.</h2>
Explanation:
Electrochemical cells primarily comprise of two half-cells. These half-cells assist in isolating the oxidation and reduction half-reactions. These two reactions are linked by a wire which allows the current to move from one edge to the other. The oxidation at the anode and the reduction take place at the cathode and the addition of a salt bridge helps in completing the circuit and permits the current to flow and leads to the generation of electricity.
