Question

I need help pleaseeeeeee

Answer 1

Step-by-step explanation:

$3 {x}^{2} - 5x + 1 = 0$

$x = \frac{-b± \sqrt{ {b }^{2} - 4ac } }{2a}$

here,a= 3 b= -5 and c= 1

$x = \frac{-( - 5)± \sqrt{ {(-5)}^{2} - 4.3.1 } }{2.3}$

$x = \frac{5 + \sqrt{13} }{6} or \frac{5 - \sqrt{13} }{6}$

option B and D

Answer 2

Answer:

Its B and D

Step-by-step explanation:

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