Answer: 115
Step-by-step explanation: just did it on edg
Answer:
(5,26)
Step-by-step explanation:
9514 1404 393
Answer:
CPCTC
Step-by-step explanation:
The applicable reason for statement 4 is "Corresponding Parts of Congruent Triangles are Congruent (CPCTC)".
The reason shown in your problem statement is applicable only within one triangle. The segments of interest are in two different triangles.
Volume = 9in • 9in • 9in
Volume = 729 in^3
Now multiply the volume by 6 grams.
Let H = total weight of the cube in terms of grams.
H = V • 6
H = 729 • 6
H = 4,374 grams
arccos (-1/2) = angle whose cosine = -1/2
= 2pi / 3
Its the first choice.