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Lubov Fominskaja [6]
3 years ago
10

Test the null hypothesis that there is no difference between the estimates of the two garages. Be sure to specify the null and a

lternative hypotheses, the test statistic with degrees of freedom, and the P-value. What do you conclude using the 0.05 significance level
Mathematics
1 answer:
Alexxx [7]3 years ago
6 0

Answer:

t = [ (x1' - x2' ) - d ] / SE . p < 0.05 suggests means are equal, p > 0.05 suggests means are unequal.

Step-by-step explanation:

Null Hypothesis [H0] : There is no difference between average estimates of two garages, M1 = M2

Alternate Hypothesis [H1] : There is difference between average estimates of two garages, M1  ≠ M2

Hypothesis can be tested by t test

t = [ (x1' - x2' ) - d ] / SE , where :-

x1' & x2' are sample means, SE = sqrt[ (s1^2/n1) + (s2^2 /n2) ] , d is the hypothesized difference between population means, and SE is the standard error ie 0 here

If the p value corresponding to calculated t value is < p value as per significance level (0.05) : We reject null hypothesis & state that M1  ≠ M2

If the p value corresponding to calculated t value >  p value as per significance level (0.05) : We accept null hypothesis & state that M1 = M2

 

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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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