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Ksivusya [100]
3 years ago
10

Part

Chemistry
1 answer:
Zielflug [23.3K]3 years ago
6 0
NaOH (aq) + HCl(aq) => NaCl(aq)+ H2O(l)

Na+(aq)+ OH - (aq) + H +(aq) +Cl - (aq) + Cl- (aq)
=> Na+(aq) + Cl - (aq) + H2O(l)
H+(aq) + OH-(aq) => H2O(l)
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To aid in the prevention of tooth decay, it is recommended that drinking water contains 0.900 ppm fluoride (F-). A) How many g o
Romashka-Z-Leto [24]

Answer:

a) <u>1.740 g</u> of F- must be added to a cylindrical water reservoir

b) Grams of sodium fluoride, NaF, that contain this much fluoride:

3.84 g

Explanation:

Step 1. calculate the volume of the tank:

Volume of cylinder =

\pi  r^{2}h ,

Here r = radius of the cylinder = d/2

h = depth = 21.80m

r=\frac{d}{2}

=\frac{3.36x10^{2}}{2}

= 168 m

Volume =

=\frac{22\times 168^{2}\times 21.80}{7}

=1.93\times 10^{6} m^{3}

2.Convert ppm to g/m3 and Solve for mass of F-

1ppm = 1g/m^{3}

0.9ppm = 0.9g/m^{3}

Because both ppm and g/m3 are same quantity .

g/m^{3} =\frac{mass\ of\ F-(g)}{Volume\ m^{3}}\times 10^{6}

0.9 =\frac{mass\ of\ F-}{1.93\times 10^{6} m^{3}}\times 10^{6}

mass\ of\ F- =1.740g

mass of F- required = 1.740 g

3. Apply <u>mole concept </u>to calculate grams of sodium fluoride produced

mass of 1 mole of F2 = 38 g

mass of 1 mole of NaF = 42 g

(from periodic table calculate molar mass)

2Na+F_{2}\rightarrow 2NaF

Here 1 mole of F2 produce = 2 mole of NaF

So,

38 g  of F2 produce = 2 x 42 g of NaF

38 g of F2 produce = 84 g of NaF

1 g of F2 produce = 84/38 g of NaF

1.74 g F2 produce =

\frac {84}{38}\times 1.74

1.74 g F2 produce = 3.84 g of NaF

3.84 g of NaF is produced

3 0
3 years ago
Using the valence bond method, explain the structure of isocyanic acid in terms of the atomic bond method.
Gala2k [10]

The structure of isocynide is

N=C

What is the importance of VSEPR theory?

Valence bond theory describes the electronic structure of molecule .The theory says that electrons fills the atomic orbitals of an atom within a molecule .

In the structure of isocynide there are triple bonds between Nitrogen and carbon . The bond length is 115.8pm and the bond angle is 180°. There is two pi and one sigma bond .

to learn more about VSEPR theory click here brainly.com/question/23129240

#SPJ9



4 0
2 years ago
Read 2 more answers
g The first step in the process is to calibrate the grating, so we know the grating spacing (the distance between the openings i
Trava [24]

Answer:

The grating spacing is  d = 1055nm

Explanation:

From the question we are told that

    The wavelength is  \lambda = 590 nm = 590 *10^{-9}m

    The angle is \theta = 34^0

    The  order of the spectrum is  n = 1

Generally in grating grating the condition for maxima   to occur is  

             d sin \theta  = n \lambda

where d is the grating spacing

     making d the subject of the formula

                  d = \frac{\lambda }{sin \theta }

        Substituting values

                  d = \frac{590 * 10^{-9}}{sin (34)}

                     d = 1055nm

8 0
3 years ago
(8.5a) Which of the following elements contains the greatest amount
Free_Kalibri [48]

Answer:

A. Chlorine

Explanation:

Chlorine has 17, Hydrogen has 1, Oxygen has 8, Sulfur has 16.

4 0
3 years ago
Place the following substances in Order of decreasing boiling point H20 N2 CO
kirill [66]

Answer:

-195.8º < -191.5º < 100º

Explanation:

Water, or H20, starts boiling at 100ºC.

Nitrogen, or N2, starts boiling at -195.8ºC.

Carbon monoxide, or C0, starts boiling at -191.5ºC.

When we place these in order from decreasing boiling point:

-195.8º goes first, then -191.5º, and 100º goes last.

4 0
4 years ago
Read 2 more answers
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