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max2010maxim [7]
3 years ago
9

Part b - the effect of an electric field (voltage) on a negatively charged oil droplet in the millikan oil droplet experiment, t

he oil is sprayed from an atomizer into a chamber. the droplets are allowed to pass through the hole into the chamber so that their fall can be observed. the top and bottom of the chamber consist of electrically charged plates. the upper plate is positively charged, and the lower plate is negatively charged. x rays are introduced into the chamber so that when they strike the oil droplets, the droplets will acquire one or more negative charges. the electric field (voltage) is applied to the metal plates. watch the animation and identify the effects of an electric field on the motion of a negatively charged oil droplet. consider the gravitational force as fg and the electric force as fe. all the other forces acting on the oil droplet can be ignored as their effect on the motion of the oil droplet is negligible. check all that apply.
Chemistry
1 answer:
AnnZ [28]3 years ago
6 0
There will be two dominant forces acting on the oil droplets. The first is the weight of the oil droplets, which will cause them to move downwards in the chamber. The other is the force of attraction the droplets will experience due to the positively charged plate and their own negative charge. The magnitude of the resultant force, which will be equivalent to the difference of these forces, will dictate whether the net movement of the droplet is downwards or upwards.
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What is an alkali metal with fewer than 10 protons in its nucleus?
Trava [24]

Answer:

            Lithium

Explanation:

                  Alkali metals are group of metals which are present in first group of periodic table. As we know atomic number is equal to number of protons contained by a particular element. Therefore, the alkali metals along with there number of protons are listed below;

Alkali Metal                                         Number of Protons

Lithium                                                               3

Sodium                                                             11

Potassium                                                         19

Rubidium                                                         37

Cesium                                                             55

Francium                                                          87

Hence, it is cleared from above table that Lithium is having fewer protons than 10.

6 0
2 years ago
A diffusion coefficient KG was determined for the diffusion of a gas A through a stagnant film B [KG = 0.88 mol//h-ft2-atm].
Angelina_Jolie [31]

Explanation:

Transfer of mass A into stagnant film B depends on the availability of driving force.

Whereas driving force is the pressure difference at the surface of A and the bulk.

As,       N_{A} \propto (P_{A1} - P_{A2})

           N_{A} = K_{G} \times (P_{A1} - P_{A2})

Therefore, putting the given values into the above formula as follows.

         N_{A} = K_{G} \times (P_{A1} - P_{A2})

                     = 0.88 \times (0.2 atm - 0.05 atm)

                     = 0.132 mol/h.ft^{2}

Thus, we can conclude that the flux of A from a surface into a mixture of A and B is 0.132 mol/h.ft^{2}

4 0
3 years ago
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joja [24]
For the purpose, we will use the equation for determining the dissociation constant from concentration and <span>percent of ionization:

Kd = c </span>× α²

α = √(Kd/c) × 100%

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c(HA) = 0.1M

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EastWind [94]

Answer:

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