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elixir [45]
4 years ago
11

Would the following errors increase, decrease, or have no effect on the calculated moles of gas collected in the experiment? Exp

lain your answers in complete sentences.
a) The measured mass of the magnesium was smaller than the true mass.
b) The actual temperature of the hydrogen gas is less than room temperature.
Chemistry
1 answer:
Nina [5.8K]4 years ago
8 0
<span>a. If the actual mass of Magnesium used was larger then the measured and the amount of gas produced should be greater
b. when gas was cooler than its surroundings its density would be greater and the volume would appear to be smaller. This is because the gas molecules are very active and when heated they will expand.
</span>so they both bound increase the calculated moles of gas collected in the experiment
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Water can be formed in the following reaction:
just olya [345]

Answer

12

Explanation

We have a balanced chemical equation from the question that depicts the formation of water.

                                                  2H2+O2-->2H2O,


We can clearly see from the equation that, the formation of 2 moles of water molecules requires the input of 2 moles of hydrogen and 1 mole of Oxygen.

So indirectly, it tells that the moles of water molecules will be double of the moles of Oxygen molecules used in the reaction.

So if we say that 6 moles of oxygen is used and the reaction is going in such a way that hydrogen is not a limiting reactant, then 12 moles of water will be produced.


Hope it help!

8 0
3 years ago
Calculate the volume of a 3.50 M solution of H2SO4 made from 49 g of H2SO4
maxonik [38]

Answer:

0.143L

Explanation:

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No of mole = mass/molar mass

No of mole= 49/98 = 0.5 mol

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Volume = n/C = 0.5/3.5 = 0.143L

3 0
3 years ago
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Alex

Answer:

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5 0
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