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elixir [45]
3 years ago
11

Would the following errors increase, decrease, or have no effect on the calculated moles of gas collected in the experiment? Exp

lain your answers in complete sentences.
a) The measured mass of the magnesium was smaller than the true mass.
b) The actual temperature of the hydrogen gas is less than room temperature.
Chemistry
1 answer:
Nina [5.8K]3 years ago
8 0
<span>a. If the actual mass of Magnesium used was larger then the measured and the amount of gas produced should be greater
b. when gas was cooler than its surroundings its density would be greater and the volume would appear to be smaller. This is because the gas molecules are very active and when heated they will expand.
</span>so they both bound increase the calculated moles of gas collected in the experiment
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Combustion of hydrocarbons such as butane () produces carbon dioxide, a "greenhouse gas." Greenhouse gases in the Earth's atmosp
Dahasolnce [82]

Answer:

1. C₄H₁₀ + ¹³/₂O₂ → 4CO₂ + 5H₂O

2. V = 596L

Explanation:

Butane (C₄H₁₀) reacts with oxygen (O₂) to produce carbon dioxide (CO₂) and water (H₂O) thus:

C₄H₁₀ + O₂ → CO₂ + H₂O

1. The balanced chemical equation is:

C₄H₁₀ + ¹³/₂O₂ → 4CO₂ + 5H₂O

2. 0,360kg of butane are:

360g×\frac{1mol}{58,12g}=<em>6,19moles of butane</em>

These moles of butane are:

6,19moles of butane×\frac{4CO_2}{1molButane}= <em>24,8 moles CO₂</em>

Using V=nRT/P

Where:

n are moles (24,8 moles CO₂); R is gas constant (0,082atmL/molK); T is temperature, 20°C (293,15K); and P is pressure (1atm).

Volume (V) is:

<em>V = 596L</em>

I hope it helps!

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3 years ago
The Formation Of Lithium Iodide
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<u>Lithium Iodide</u><u>:</u>

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6 0
3 years ago
What is the speed of a car that traveled 40.2km in 2 hours?
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2 years ago
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A cylinder is filled with 10.0L of gas and a piston is put into it. The initial pressure of the gas is measured to be 209.kPa. T
disa [49]

Answer : The final pressure of the gas will be, 26.8 kPa

Explanation :

According to the Boyle's law, the pressure of the gas is inversely proportional to the volume of the gas at constant temperature of the gas and the number of moles of gas.

P\propto \frac{1}{V}

or,

PV=k

or,

P_1V_1=P_2V_2

where,

P_1 = initial pressure of the gas = 209 kPa

P_2 = final pressure of the gas = ?

V_1 = initial volume of the gas = 10.0 L

V_2 = final volume of the gas = 78.0 L

Now put all the given values in this formula, we get the final pressure of the gas.

209kPa\times 10.0L=P_2\times 78.0L

P_2=26.8kPa

Therefore, the final pressure of the gas will be, 26.8 kPa

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3 years ago
What type of elements form metallic bonds?​
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