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lilavasa [31]
3 years ago
8

Molly walked 3.45 miles on a hike. Her sister walked 1.23 miles. Her brother walked 0.85 miles. Round each distance to the neare

st tenth of a mile. About how much further did Molly walk than her brother and sister combined? A. about 1.2 miles B. about 1.4 miles C. about 2.2 miles D. about 2.4 miles
Mathematics
2 answers:
Lemur [1.5K]3 years ago
6 0
We know that 4 and below rounds down and 5 and above round up

That means she walked 3.5 miles   her sister walked 1.2 miles

and her brother walked 0.9 miles

1.2+0.9=2.1 

3.5-2.1=1.4

B about 1.4 miles
Alex787 [66]3 years ago
4 0

Answer:

B about 1.4 miles Hope this helps!! :)

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Answer:

15/6 pieces of pizza were eaten. Which is equivalent to 2.5. So 2.5 pizzas were eaten.

Step-by-step explanation:

Just did the math. Convert 4 1/3 to 0/6. So 1 times 2 is 2, and 3 times 2 is 6. Which would give you 4 2/6 which has the same denominator as 1 5/6.

8 0
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Answer:

Therefore,

a_{21}=2

Step-by-step explanation:

Given:

A=\left[\begin{array}{ccc}3&6&9\\2&4&8\\\end{array}\right]

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a₂₁ = ?

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Let,

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5 0
3 years ago
Which of the binomials below is a factor of this trinomial?<br> 4x2 + 21x + 5
guapka [62]

Answer:

B.  4x + 1

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Answer

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8 0
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A professor went to a website for rating professors and looked up the quality rating and also the "easiness" of the six full-tim
Marat540 [252]

We are asked to determine the correlation factor "r" of the given table. To do that we will first label the column for "Quality" as "x" and the column for "Easiness" as "y". Like this:

Now, we create another column with the product of "x" and "y". Like this:

Now, we will add another column with the squares of the values of "x". Like this:

Now, we add another column with the squares of the values of "y":

Now, we sum the values on each of the columns:

Now, to get the correlation factor we use the following formula:

r=\frac{n\Sigma xy-\Sigma x\Sigma y}{\sqrt{(n\Sigma x^2-(\Sigma x)^2)(n\Sigma y^2-(\Sigma y)^2)}}

Where:

\begin{gathered} \Sigma xy=\text{ sum of the column of xy} \\ \Sigma x=\text{ sum of the column x} \\ \Sigma y=\text{ sum of the column y} \\ \Sigma x^2=\text{ sum of the column x\textasciicircum2} \\ \Sigma y^2=\text{ sum of the column y\textasciicircum2} \\ n=\text{ number of rows} \end{gathered}

Now we substitute the values, we get:

r=\frac{\left(6)(70.56)-(25.2)(16.4\right)}{\sqrt{((6)(107.12)-(25.2)^2)((6)(47.82)-(16.4)^2)}}

Solving the operations:

r=0.858

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7 0
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