The answer is III. only
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Answer:
0.76
Step-by-step explanation:
-8+3=-6x^(2/3)
-5=-6 x^(2/3)
-5/-6=x^(2/3)
(2/3)√{5/6}=x
0.76=x
x=0.76
Let
denote the rocket's position, velocity, and acceleration vectors at time
.
We're given its initial position

and velocity

Immediately after launch, the rocket is subject to gravity, so its acceleration is

where
.
a. We can obtain the velocity and position vectors by respectively integrating the acceleration and velocity functions. By the fundamental theorem of calculus,


(the integral of 0 is a constant, but it ultimately doesn't matter in this case)

and



b. The rocket stays in the air for as long as it takes until
, where
is the
-component of the position vector.

The range of the rocket is the distance between the rocket's final position and the origin (0, 0, 0):

c. The rocket reaches its maximum height when its vertical velocity (the
-component) is 0, at which point we have


Answer:
False
Step-by-step explanation:
girls : boys : total
5 : 6 :11
Multiply each term by 2
10: 12 :22
Ratio of girls to boys
10:12
Divide by 2
5:6
The ratio of girls to boys is still 5:6 but the total students is 22
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