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olchik [2.2K]
3 years ago
12

How many grams of CO2 are in 11 mol of the compound?

Chemistry
2 answers:
dolphi86 [110]3 years ago
7 0
11 × 44 = 484 g

mol × molar mass
nataly862011 [7]3 years ago
6 0

<u>Answer: </u>484 grams of CO_2 are present in given moles of the compound.

<u>Explanation:</u>

To calculate the mass of carbon dioxide, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

We are given:

Moles of CO_2 = 11 mol

Molar mass of CO_2 = [12 + (2 × 16)] = 44 g/mol

Putting values in above equation, we get:

11mol=\frac{\text{Mass of }CO_2}{44g/mol}\\\\\text{Mass of }CO_2=484g

Hence, the mass of carbon dioxide is 484 grams.

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Using standard heats of formation, calculate the standard enthalpy change for the following reaction. 2NH3(g) 3N2O(g)4N2(g) 3H2O
trasher [3.6K]

Answer: \Delta H^{0} = -879.15 kJ/mol

Explanation: <u>Heats</u> <u>of</u> <u>formation</u> is the amount of heat necessary to create 1 mol of a compound from its molecular constituents. The basic conditions the substance is formed is at standard conditions: 1 atm and 25°C. Each compound has its own heat of formation per mol of compound (kJ/mol), but to an element is assigned a value of zero.

<u>Standard</u> <u>Enthalpy</u> <u>Change</u> is defined as the heat absorbed or released when a reaction takes place. It can be positive or negative, which means reaction is endothermic or exothermic, respectively.

Enthalpy change is calculated as the difference between the sum of heat formation of products and the sum of heat formation of the reactants:

\Delta H^{0}=\Sigma H^{0}_{f}_{(products)}-\Sigma H^{0}_{f}_{(reactants)}

For the reaction

   2NH₃   +      3N₂O   →      4N₂    +     3H₂O

2(-46.2)   +     3(82.05)      4(0)    +    3(-241.8)

\Delta H^{0}=3(-241.8)-[ 2(-46.2)+3(82.05)]

\Delta H^{0}=-725.4-153.75

\Delta H^{0}=-879.15

<u>The standard enthalpy change for the reaction is </u>\Delta H^{0}=-879.15<u> kJ</u>

8 0
3 years ago
WILL GIVE BRAINLIEST
erastova [34]

Answer:

It is a force acting on the object.

Explanation:

The answer option which is true about the weight of an object is: C. It is a force acting on the object.

Weight can be defined as the force acting on a physical body or an object as a result of gravity. Also, the weight of an object is measured in Newton.

Mathematically, the weight of an object is given by the formula;

Where;

m is the mass of the object.

g is the acceleration due to gravity.

In conclusion, the weight of an object is the force acting on an object due to gravity.

4 0
2 years ago
(a) What characteristic functional group do you expect to see in the IR spectrum, that is indicative of eugenol? (b) What wavenu
Darina [25.2K]

Answer:

a) The functional group that will be evident in the IR spectrum is the OH group.

b) OH group appears between 3200-3600 cm⁻¹

c) An important impurity that have the same functional group is water.

Explanation:

Eugenol is a chemical substance that consist in a benzene that have in 1 an alcohol, in position 2 a methyl ether and in position 4 an 1-propene bonded by the terminal alkyl carbon.

a) Having this in mind, the functional group that will be evident in the IR spectrum is the OH group.

b) This OH group appears between 3200-3600 cm⁻¹

c) An important impurity that have the same functional group is water. When you have water in your sample a big signal will appear in this zone and it is possible that overlapes the OH signal of eugenol.

I hope it helps!

5 0
4 years ago
Calculate the mean of 2, 5 and 3. write your answer to 2 decimal places. please help me on this
makvit [3.9K]

Hello.

The answer is: 3.3333

To get the answer add 2,5 and 3 that is 10 then divide by 3 to get 3.3

Have a nice day

6 0
3 years ago
5. an atom that has lost or gained an electron and has become charged
densk [106]

Answer:

It would be compound.

Explanation:

It is this way because if it adds another proton it becomes more positive that nuetral, and if you add an electron it just makes the atom more dense. That is why the answer is compound. Hope this helped :)

5 0
3 years ago
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