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3 years ago

How many grams of CO2 are in 11 mol of the compound?

Chemistry

2 answers:

dolphi86 [110]3 years ago

7 0

11 × 44 = 484 g

mol × molar mass

nataly862011 [7]3 years ago

6 0

Answer: 484 grams of $CO_2$ are present in given moles of the compound.

Explanation:

To calculate the mass of carbon dioxide, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

We are given:

Moles of $CO_2$ = 11 mol

Molar mass of $CO_2$ = [12 + (2 × 16)] = 44 g/mol

Putting values in above equation, we get:

$11mol=\frac{\text{Mass of }CO_2}{44g/mol}\\\\\text{Mass of }CO_2=484g$

Hence, the mass of carbon dioxide is 484 grams.

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By mistake, you added salt instead of sugar to the oil. How can you remove the salt?

Ghella [55]

Explanation:

To remove the salt from the oil, I will add water to dissolve the salt from it.

Oil is an organic molecule that is non-polar

Salt is polar ionic compound

Salt will not dissolve in the oil.

Take the mixture.
Add water to it.
Water and oil are immiscible
Shake the new heterogeneous mixture vigorously.
leave to settle.
Oil will come on top of the water.
You can skim off the oil layer on top.
Then heat the water and salt solution.
This leaves the oil behind.

learn more:

Mixture brainly.com/question/1832352

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5 0

3 years ago

Read 2 more answers

Mass=35g, density=5g/cm3. what is the volume?

nevsk [136]

Answer:

7 cm^3

Explanation:

Density = Mass/Volume

5 = 35/x

multiply both sides by x to get

5x = 35

then divide by 5

so x = 7 cm^3

8 0

2 years ago

Convert 15.2 moles of K to atoms of K.

choli [55]

Answer:

$\boxed {\boxed {\sf 9.15*10^{24} \ atoms \ K}}$

Explanation:

To convert atoms to moles, Avogadro's Number must be used: 6.022*10²³.

This tells us the amount of particles (atoms, molecules, etc.) in 1 mole of a substance. In this case it is the atoms of potassium. We can create a ratio.

$\frac {6.022*10^{23} \ atoms \ K }{ 1 \ mol \ K }$

Multiply by the given number of moles: 15.2

$15.2 \ mol \ K *\frac {6.022*10^{23} \ atoms \ K }{ 1 \ mol \ K }$

The moles of potassium cancel.

$15.2 *\frac {6.022*10^{23} \ atoms \ K }{ 1 }$

The denominator of 1 can be ignored.

$15.2 * {6.022*10^{23} \ atoms \ K }{$

Multiply.

$9.15344*10^{24} \ atoms \ K$

The original measurement of moles has 3 significant figures, so our answer must have the same. For the number we calculated that is the hundredth place. The 3 in the thousandth place tells us to leave 5.

$9.15*10^{24} \ atoms \ K$

In 15.2 moles of potassium, there are 9.15*10²⁴ atoms of potassium.

3 0

3 years ago

What is the vapor pressure of the solution if 35.0 g of water is dissolved in 100.0 g of ethyl alcohol at 25 ∘C? The vapor press

masya89 [10]

Answer: The vapor pressure of the solution is 43.55 mmHg

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

For water:

Given mass of water = 35.0 g

Molar mass of water = 18 g/mol

Putting values in equation 1, we get:

$\text{Moles of water}=\frac{35.0g}{18g/mol}=1.944mol$

For ethyl alcohol:

Given mass of ethyl alcohol = 100.0 g

Molar mass of ethyl alcohol = 46 g/mol

Putting values in equation 1, we get:

$\text{Moles of ethyl alcohol}=\frac{100.0g}{46g/mol}=2.174mol$

Total moles of solution = [1.944 = 2.174] moles = 4.118 moles

Mole fraction of a substance is given by:

$\chi_A=\frac{n_A}{n_A+n_B}$

For water:

$\chi_{\text{water}}=\frac{n_{\text{water}}}{n_{\text{water}}+n_{\text{ethyl alcohol}}}$

$\chi_{water}=\frac{1.944}{4.118}=0.472$

For ethyl alcohol:

$\chi_{\text{ethyl alcohol}}=\frac{n_{\text{ethyl alcohol}}}{n_{\text{water}}+n_{\text{ethyl alcohol}}}$

$\chi_{\text{ethyl alcohol}}=\frac{2.174}{4.118}=0.528$

Dalton's law of partial pressure states that the total pressure of the system is equal to the sum of partial pressure of each component present in it.

To calculate the vapor pressure of the solution, we use the law given by Dalton, which is:

$P_T=\sum_{i=1}^n (p_i\times \chi_i)$

Or,

$P_T=[(p_{\text{water}}\times \chi_{\text{water}})+(p_{\text{ethyl alcohol}}\times \chi_{\text{ethyl alcohol}}$

We are given:

Vapor pressure of water = 23.8 mmHg

Vapor pressure of ethyl alcohol = 61.2 mmHg

Putting values in above equation, we get:

$p_T=[(23.8\times 0.472)+(61.2\times 0.528)]\\\\p_T=43.55mmHg$

Hence, the vapor pressure of the solution is 43.55 mmHg

4 0

3 years ago

142 amu of chlorine would contain

zhuklara [117]

Answer: There are four atoms

Explanation: mass of Cl atom is 35.45 amu

Amount of atoms n = m/M = 142 / 35.45 = 4

5 0

2 years ago