Ask question

Ask question

All categories

3 years ago

14

If an element has 3 valence electrons, what charge will likely form on its ion? Hint: It will lose those electrons. What happens

to the charge when it loses 3 electrons?
A, +3
B, -3
C. +5
D, -5

1 answer:

guajiro [1.7K]3 years ago

6 0

Answer:

The answer to your question is: letter A

Explanation:

If an atom lose 3 electrons its charge will be positive, it will be +3

You might be interested in

What can liquids and gases do that solids cannot?

Aleks [24]

Answer:

What can liquids do that solids cannot?Liquids will flow and fill up any shape of container. Solids like to hold their shape. In the same way that a large solid holds its shape, the atoms inside of a solid are not allowed to move around too much. Atoms and molecules in liquids and gases are bouncing and floating around, free to move where they want.

What can gases do that solids cannot?The atoms and molecules in gases are much more spread out than in solids or liquids. They vibrate and move freely at high speeds. A gas will fill any container, but if the container is not sealed, the gas will escape. Gas can be compressed much more easily than a liquid or solid.

I hope this helps

5 0

2 years ago

A 29.7 g sample of iron ore is treated as follows. The iron in the sample is all converted by a series of chemical reactions to

Softa [21]

<u>Answer:</u> The mass of iron in the ore is 10.9 g

<u>Explanation:</u>

We are given:

Mass of iron (III) oxide = 15.6 g

We know that:

Molar mass of Iron (III) oxide = 159.69 g/mol

Molar mass of iron atom = 55.85 g/mol

As, all the iron in the ore is converted to iron (III) oxide. So, the mass of iron in iron (III) oxide will be equal to the mass of iron present in the ore.

To calculate the mass of iron in given mass of iron (III) oxide, we apply unitary method:

In 159.69 g of iron (III) oxide, mass of iron present is $(2\times 55.85)=111.7g$

So, in 15.6 g of iron (III) oxide, mass of iron present will be = $\frac{111.7g}{159.69g}\times 15.6g=10.9g$

Hence, the mass of iron in the ore is 10.9 g

7 0

3 years ago

Arrange the molecules H2O, NH3, Ar, NaCl in order of expected increasing boiling points. 1. None of these 2. NaCl, H2O, NH3, Ar

Aleks04 [339]

Answer:

Option (4) is correct

Explanation:

NaCl is an ionic solid. $Na^{+}$ and $Cl^{-}$ ions are held together by strong coloumbic attractive force. Hence NaCl has highest boiling point'
Ar is a monoatomic molecule. Hence only weak london dispersion force exists between Ar atom/molecules. Hence it requires lowest amount of energy to boil and thereby possess lowest boiling point.
$NH_{3}$ and $H_{2}O$ are polar protic molecules. Hence they possess london dispersion force, dipole-dipole force and hydrogen bonding as intermolecular forces.
Dipole-dipole force is stronger in $H_{2}O$ than $NH_{3}$ due to more polar O-H bond than N-H bond. Also molecular weight of $H_{2}O$ is higher than $NH_{3}$ . So, more energy is required to boil $H_{2}O$ . So, $H_{2}O$ has higher boiling point than $NH_{3}$

Hence order of boiling point : $NaCl>H_{2}O>NH_{3}>Ar$

4 0

3 years ago

Which of the following weighs least?

Lunna [17]

Answer:

A

Explanation:

0.2g of atom of nitrogen is the one that weigh least cause of.2g is not up to one mole of nitrogen

7 0

3 years ago

CAN HF USED TO CLEAVE ETHERS EXPLAIN

PilotLPTM [1.2K]

Answer:

no

Explanation:

Fluoride is not nucleophilic (having the tendency to donate electrons) enough to allow for the use of HF to cleave ethers in protic media(protic solvents are polar liquid compounds that have dissociable hydrogen atoms). The rate of reaction is comparably low, so that heating of the reaction mixture is required.

4 0

3 years ago