Answer:
The rate of transfer of heat is 0.119 W
Solution:
As per the question:
Diameter of the fin, D = 0.5 cm = 0.005 m
Length of the fin, l =30 cm = 0.3 m
Base temperature,
Air temperature,
k = 388 W/mK
h =
Now,
Perimeter of the fin, p =
Cross-sectional area of the fin, A =
A =
To calculate the heat transfer rate:
where
Now,
A ) The first ball:
h = v o * t - g t² / 2
19.6 = 14.7 t + 9.8 t²/2
4.9 t² + 14.7 t - 19.6 = 0
t 1/2 = (-14.7 +/- √216.09+384.16 ) / 9.8 = 9.8/9.8 = 1 s
The second ball:
v = v o - g t
0 = 14.7 - 9.8 t
9.8 t = 14.7
t = 1.5 ( upward )
h = 19.6 + 14.7 - 9.8 * 1.5 = 30.625 m
30.625 = 9.8 * t²/2
t² = 6.25
t = 2.5 s ( downward )
1.5 s + 2.5 s = 4 s
The difference: 4 s - 1 s = 3 s.
B ) The first ball:
v = v o + g t = 14.7 + 9.8 * 1 = 24.5 m/s
The second ball:
v = g * t = 9.8 * 3 = 24.5 m/s
C ) d 1 = 14.7 * 0.8 + 9.8 * 0.8²/2 = 11.76 + 3.136 = 14.896 m
d 2 = 14.7 * 0.8 - 9.8* 0.8²/2 = 11.76 - 3.136 = 8.624 m
d 1 + d 2 = 14.896 + 8.624 = 23.52 m
If you meant "kinetics" then kinetics is the study of body movement.