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denis23 [38]
3 years ago
8

Alexis pulls with 3.0 Newton’s on a toy doll toward east. Brianna pulls on the same toy toward the south with 2.0 Newton’s. Calc

ulate the magnitude of the resultant force on the toy.

Physics
2 answers:
xeze [42]3 years ago
8 0

Answer:

3.605N

Explanation:

From the diagram attached, the resultant force can be calculated using pythagoras theorem,

R² = F1² + F2²

R² = 3² + 2²

R² = 9 + 4

R² = 13

R = 3.605N

Note: the square root of R was taken

jeka57 [31]3 years ago
6 0

Brianna pulls on the same toy toward the south with 2.0 ... Calculate the magnitude of the resultant force on the toy

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The table shows information about four students who are running around a track. Which statement is supported by the information
murzikaleks [220]

Answer:

Mohammed has less kinetic energy than Autumn

Explanation:

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K=\frac{1}{2}mv^2

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v is the speed of the student

Let's use the formula above to calculate the kinetic energy of each student:

- Autumn: K=\frac{1}{2}(50 kg)(4 m/s)^2=400 J

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- Lexy: K=\frac{1}{2}(53 kg)(3 m/s)^2=238.5 J

- Chiang: K=\frac{1}{2}(64 kg)(5 m/s)^2=800 J

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7 0
3 years ago
Read 2 more answers
Derive a general formula for projectile motion with the object launched at an angle
vagabundo [1.1K]

Answer:

  y = x tan θ - (g / 2v₀² cos² θ) x²

Explanation:

An equation is called a general formula that relates the position on the x-axis and the height on the body's axis.

Let's write the position on each axis

X axis. No acceleration

         x = v₀ₓ t

Y Axis.  There is the acceleration of gravity

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Let's clear the time in the first equation and substitute in the second

       y = v₀ sin θ  (x / v₀ₓ) - ½ g (x / v₀ₓ)²

       y = v₀ sin θ / v₀ cos θ x - ½ g x² / v₀² cos² θ

       y = x tan θ - (g / 2v₀² cos² θ) x²

This is the trajectory equation in projectile launching

6 0
3 years ago
A block sliding across a level surface has a mass of 2.5 kg and a mechanical energy of 20 joules. What is its velocity?
tia_tia [17]
Hi!

The energy of the block is 4 m/s

To calculate this, you need to use the equation for kinetic energy. The block is sliding (i.e. it's moving). If the object is sliding across a level surface, the only energy it has is kinetic energy, because there is no change in potential energy (which changes with height). So, the mechanical energy will be pure kinetic energy. The equation is the following, derived from the expression for kinetic energy:

v= \sqrt{ \frac{2*Ke}{m}}=\sqrt{ \frac{2*20 (kg*m^{2}*s^{-2}) }{2,5kg}}=4 m/s

Have a nice day!
8 0
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