Question

Samuel places a ladder against his house. The base of the

Answer 1

Answer:

d. 8 feet

Explanation:

(height)^2 = (10)^2 - (6)^2

= 100 - 36

height = √64

= 8 feet

Answer 2

Answer:

d. 8 feet

Explanation:

let :

a = length of the ladder = 10 feet

b = how high above the ground the ladder touches the wall

c = the length of the base of the ladder from the wall . 6 feet

• By Pythagoras' theorem

${a }^{2} = {b}^{2} + {c}^{2}$

• Therefore
• ${b}^{2} = {a}^{2} - {c}^{2}$
• ${b}^{2} = {10}^{2} - {6}^{2}$

${b}^{2} = 100 - 36$

• ${b}^{2} = 64$
• Square root both sides
• $\sqrt{ {b}^{2} } = \sqrt{64}$
• $b = 8$
• Therefore 8 feet above the ground the ladder touches the wall