Answer;
= 60 m
Explanation;
s = 80 m
= ½at² = ½ * 9.8m/s² * t² → t = 4.04 s
At any time 0 ≤ t ≤ 4.04 s, height is
y = Yo + ½at² = 80 m - 4.9m/s² * t²
so at t = 4.04s/2 = 2.02 s,
y = 80 m - 4.9m/s² * (2.02s)² = 60 m
(so it drops 15 m during the first 2.02 s and 60 m during the second 2.02 s)
Swept-frequency pulses have found use in a variety of fields, including spectroscopic methods where effective spin control is necessary.
To find more, we have to study about the spectroscopic methods.
<h3>
What is homonuclear decoupling and broadband excitation?</h3>
- A thorough understanding of the evolution of spin systems during these pulses is crucial for many of these applications since it not only helps to describe how procedures work but also makes new methodologies possible.
- Broadband inversion, refocusing, and excitation employing these pulses are some of the most popular applications in NMR, ESR, MRI, and in vivo MRS in magnetic resonance spectroscopy.
- A generic expression for chirped pulses will be presented in this study, along with numerical methods for calculating the spin dynamics during chirped pulses using solutions along with extensive examples.
Thus, we can conclude that, the swept-frequency pulses have found use in a variety of fields, including spectroscopic methods where effective spin control is necessary.
Learn more about the broadband excitation here:
brainly.com/question/19204110
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Answer:
Conductors allow electric charges to move freely
We Know, Power = Energy/Time
Substitute the known value. which is P = 350 watt, & T = 30 sec
350 = E/30
E = 350 * 30
E = 1050 Joules.
So, your answer is 1050 Joules.
Hope this helps! Keep studying!