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Ronch [10]
3 years ago
6

Derive a general formula for projectile motion with the object launched at an angle

Physics
1 answer:
vagabundo [1.1K]3 years ago
6 0

Answer:

  y = x tan θ - (g / 2v₀² cos² θ) x²

Explanation:

An equation is called a general formula that relates the position on the x-axis and the height on the body's axis.

Let's write the position on each axis

X axis. No acceleration

         x = v₀ₓ t

Y Axis.  There is the acceleration of gravity

        y = v_{oy} t - ½ g t²

Let's clear the time in the first equation and substitute in the second

       y = v₀ sin θ  (x / v₀ₓ) - ½ g (x / v₀ₓ)²

       y = v₀ sin θ / v₀ cos θ x - ½ g x² / v₀² cos² θ

       y = x tan θ - (g / 2v₀² cos² θ) x²

This is the trajectory equation in projectile launching

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Which statements describe science? Check all that apply. It lacks a formal process. It involves observation. It involves experim
scoray [572]

Answer:

It involves observation

It involves experimentation

It is supported by evidence

Explanation:

Science can be described as a system of knowledge based on the understanding of the natural world. The subject of science requires the scientific method - a chronological series of steps that have to be followed while trying to understand events in the natural world. These steps are:

  • <em>observation</em>
  • <em>formulation of hypothesis</em>
  • <em>testing of the hypothesis by experimentation</em>
  • <em>conclusion based on available evidence from the experiment</em>

Hence, science involves <u>observation</u>, <u>experimentation</u>, and <u>it is supported by evidence</u>.

5 0
3 years ago
A car is traveling at 16 m/s^2
Leya [2.2K]
Really? wow that's pretty cool
4 0
4 years ago
In an experiment, it took 300s to increase the temperature of 0.1kg of the liquid from 25°C to 50°C. During this period, the ene
klemol [59]

Answer:

<h2>4000 \textbf{J}\text{ }\textbf{kg}^{\textbf{-1}}\text{ }\textbf{K}^{\textbf{-1}} </h2>

Explanation:

        The temperature of 0.1 kg of liquid rises from 25°C to 50°C in 300 sec. Energy of 13,600 J was supplied during this time. Appartus was losing energy at the rate of 12 J/sec.

       Let us assume the Specific heat capacity as s.

      As there is no state change from liquid to gas, only Specific heat capacity is involved. Also, work done is approximately zero because volume does not change much. So,

       Energy gained = Energy required to rise the temperature

       Energy gained by liquid = 13600\text{ }J-(300\text{ }sec)\times(12\text{ }\frac{J}{sec})=10000\text{ }J

       10000\text{ }J=m\times s\times\Delta T=(0.1\text{ }kg)\times(s)\times(323K-298K)=2.5s\text{ }kgK\\s=4000\text{ }\frac{J}{kg.K}

∴ Specific heat capacity of liquid = 4000 \frac{J}{kg.K}

4 0
3 years ago
What is the acceleration an object experiences on earth?w?
mariarad [96]
9.8 m/s^s and thats the earths gravitational force!
Hope it helps
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3 years ago
15. Meteoroids can form when comets break apart, creating dust clouds.
Liula [17]

Answer (s):

15. True

16. False

17. True

7 0
4 years ago
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