Answer: ABCD is a quadrilateral
To prove : ∠AOB=
2
1
(∠C+∠D)
AO and BO is bisector of A and B
∠1=∠2∠3=∠4...(1)
∠A+∠B+∠C+∠D=360
(Angle sum property)
2
1
(∠A+∠B+∠C+∠D)=180...(2)
In △AOB
∠1+∠3+∠5=
2
1
(∠A+∠B+∠C+∠D)
∠1+∠3+∠5=∠1+∠3+
2
1
(∠C+∠D)
∠AOB=
2
1
(∠C+∠D)
Explanation: In a quadrilateral ABCD. AO and BO are bisectors of angle A and angle B respectively. Prove that ∠AOB=
2
1
{∠C+∠D}.
Absolute value functions are v-shaped. I hthink the turning point you're referring to is the vertex. This is where the inside of the absolute value is zero.
f(x) = |x+2|
0 = x+2
-2 = x
vertex (-2,0)
Answer:
amplitude = 3, period = , and frequency = 2
super sorry if this is wrong but I hope this is right
Answer:
x = 50°
Step-by-step explanation:
Angles in a quadrilateral add to 360°
First work out the interior missing angle
360° - ( 40° + 80° + 110° ) = 130°
Angles on a straight line add to 180° so
180° - 130° = 50°
Answer:
A) 0.8
Step-by-step explanation:
0.8 on edge.
