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valentina_108 [34]
3 years ago
7

Which statement is true?

Mathematics
2 answers:
Nataliya [291]3 years ago
7 0

Answer:

D

Step-by-step explanation:

We can see in the graph f(x) that the x intercept is (1,0).

In the table of g(x), we can see that the x intercept is (-1,0).

Since 1>-1, the x intercept of the graph f(x) is greater than the x intercept of graph g(x).

sertanlavr [38]3 years ago
7 0

ANSWER

D. The x-intercept of f(x) is greater than the x-intercept of g(x).

EXPLANATION

From the graph, f(x) touches the y-axis at y=-1.

The y-intercept of -1

The graph touches the x-axis at x=1.

This is the x-intercept.

From the table, the y-intercept is the point with x-coordinate of zero.

From the table, x=0 when y=1.

The y-intercept of g(x) is 1.

The x-intercept is where y=0.

The x-intercept is -1.

The x-intercept of f(x), which is 1, is greater than the x-intercept of g(x), which is -1

The correct choice is D.

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Fittoniya [83]

Answer:

So starting with:  

1000 ft / 5 min  

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1000 ft / 5 min (1/60 min/sec) (1 kt / 1.68780986 ft/sec)  

1.974946 kt

Step-by-step explanation:

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8 0
3 years ago
Read 2 more answers
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-Dominant- [34]

Answer:

4.56, 4,65, 5,46, 5.64, 6.45 and 6.54

Step-by-step explanation:

start with the whole number and find the smallest one!

It would be 4 then find the number with the smallest amount

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4 0
3 years ago
Solve for x x−3/11=8<br><br>x=​
Svet_ta [14]

Answer:

x = 91/11

Step-by-step explanation:

1. x - 3/11 = 8

2. add 3/11 to both sides of the equation

3. x = 91/11

8 0
3 years ago
Mr .Baker has baked some muffins. If he packs them in boxes of 4, he will have 3 left over. If he packs them in boxes of 5, he w
babunello [35]

Answer:

\boxed{43}

Step-by-step explanation:

I think the easiest way to solve this problem is by brute force: trial and error.

We must find numbers that when divided by  

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  • 5 leave 3 (5n + 3)
  • 6 leave 1  (6n + 1)

Here is a list of multiples of the integer n that satisfy the three conditions. \begin{array}{c|ccc}\mathbf{n} & \mathbf{4n+ 3} & \mathbf{5n + 3} & \mathbf{6n + 1}\\1 & 7 & 8 & 7\\2 & 11 & 13 & 13\\3 & 15 & 18 & 19\\4 & 19 & 23 & 25\\5 & 23 & 28 & 31\\6 & 27 & 33 & 37\\7 & 31 & 38 & \mathbf{43}\\8 & 35 & \mathbf{43} & 49\\9 & 39 & 48 & 55\\10 & \mathbf{43} & 53 & 61\\\end{array}\\\text{The only number that is common to all three lists is $\mathbf{43}$.}\\\text{The smallest possible number of muffins Mr. Baker could have baked is $\boxed{\mathbf{43}}$.}

Check:

43 \div 4 = 10R3\\43 \div5 = 8R3\\43 \div 6 = 7R1

OK .

6 0
3 years ago
1/8 + 2(1/2m + 5) = 1/4m + 7
Neporo4naja [7]
<span>1/8 + 2(1/2m + 5) = 1/4m + 7 would equal m=-25/6</span>
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4 years ago
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