Due to law of conservation of mass, the mass will not change.
in an open container the weight will change as when the chemical reaction goes, carbonic acid, H2CO3 forms which decomposes into CO2 and H2O, and the CO2 will release, decreasing the weight.
Answer:
1.8 moles
Explanation:
Number of moles = ?
Pressure = 15.4 atm
Volume = 2.92L
Temperature = 32°C = (32 + 273.15)K = 305.15K
From ideal gas equation,
PV = nRT
P = pressure of the ideal gas
V = volume in which the gas occupies
n = number of moles
R = ideal gas constant = 0.082J/mol.K
T = temperature of the gas
PV = nRT
n = PV / RT
n = (15.4 * 2.92) / (0.082 * 305.15)
n = (44.968 / 25.0223)
n = 1.797 moles = 1.8 moles
Number of moles of the gas is 1.8 moles
C)
Explanations
Approach A: Comparison of the bonding atoms
What element(s) does each species comprise?
- carbon monoxide- one metalloid, carbon, bonded to one nonmetal
- oxygen- one nonmetal
- lithium bromide- one metal and one nonmetal
- ammonia- two nonmetals
Lithium bromide is the only substance that features a metal element bonded to a nonmetal element among all four species in the list. It takes significant differences in electronegativity for the bonding atoms in a binary compound to ionize and form an ionic compound. Therefore the species in question shall contain at least one metal element bonded to one nonmetal.
Approach B: Comparison of melting points
Recall the physical state of the species under room temperature and pressure:
- carbon monoxide- gas
- oxygen- gas
- lithium bromide- ?
- ammonia- gas
Ionic bonds hold ions in an ionic compound in place with great degrees of rigidity. In contrast, covalent molecules adhere to each other with intermolecular interactions that are weaker by magnitudes. It's unlikely for ionic crystals to behave as gases under standard conditions. Thus A, B, D cannot be ionic compounds.
<u>Ans: Volume of stock H2SO4 required = 6.94 ml</u>
<u>Given:</u>
Concentration of stock H2SO4 solution M1 = 18.0 M
Concentration of the final H2SO4 solution needed M2 = 2.50 M
Final volume of H2SO4 needed, V2 = 50.0 ml
<u>To determine:</u>
Volume of stock needed, V1
Explanation:
Use the dilution relation:
Letter D.
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