Answer:
Excretion is the process of removing wastes from the body. Organs of the excretory system include the kidneys, large intestine, skin, and lungs.
The excretory system removes metabolic wastes from the body. The major organs of excretion are the kidneys, a pair of bean-shaped organs located below the liver. The kidneys filter blood and regulate water balance in the body
Answer:
<h2>2</h2>
Explanation:
The pH of a solution can be found by using the formula
![pH = - log [ {H}^{+} ]](https://tex.z-dn.net/?f=pH%20%3D%20-%20log%20%5B%20%7BH%7D%5E%7B%2B%7D%20%5D)
From the question we have
![pH = - log(1.0 \times {10}^{ - 2} ) \\ = 2](https://tex.z-dn.net/?f=pH%20%3D%20%20-%20%20log%281.0%20%5Ctimes%20%20%7B10%7D%5E%7B%20-%202%7D%20%29%20%20%5C%5C%20%20%3D%202)
We have the final answer as
<h3>2</h3>
Hope this helps you
Answer:
First, precipitate of AgCl is formed. Second, a soluble complex of silver and ammonia is formed. Third, AgCl is reproduced due to disappearance of ammonia complex in presence of
.
Explanation:
In presence of NaCl,
forms an insoluble precipitate of AgCl.
Reaction: ![Ag^{+}(aq.)+Cl^{-}(aq.)\rightarrow AgCl(s)](https://tex.z-dn.net/?f=Ag%5E%7B%2B%7D%28aq.%29%2BCl%5E%7B-%7D%28aq.%29%5Crightarrow%20AgCl%28s%29)
In presence of
, AgCl gets dissolved into solution due to formation of soluble
complex.
Reaction: ![AgCl(s)+2NH_{3}(aq.)\rightarrow [Ag(NH_{3})_{2}]^{+}(aq.)+ Cl^{-}(aq.)](https://tex.z-dn.net/?f=AgCl%28s%29%2B2NH_%7B3%7D%28aq.%29%5Crightarrow%20%5BAg%28NH_%7B3%7D%29_%7B2%7D%5D%5E%7B%2B%7D%28aq.%29%2B%20Cl%5E%7B-%7D%28aq.%29)
In presence of
,
complex gets destroyed and free
again reacts with free
to produce insoluble AgCl
Reaction: ![[Ag(NH_{3})_{2}]^{+}(aq.)+2H^{+}(aq.)+Cl^{-}(aq.)\rightarrow AgCl(s)+2NH_{4}^{+}(aq.)](https://tex.z-dn.net/?f=%5BAg%28NH_%7B3%7D%29_%7B2%7D%5D%5E%7B%2B%7D%28aq.%29%2B2H%5E%7B%2B%7D%28aq.%29%2BCl%5E%7B-%7D%28aq.%29%5Crightarrow%20AgCl%28s%29%2B2NH_%7B4%7D%5E%7B%2B%7D%28aq.%29)
Answer:
the only remote information i could find about this element was sodium
dicyanidoaurate(I)
sodium dicyanoaurate(1-)
Na[Au(CN)2]
sodium dicyanidoaurate(1-)
but as you see these go towards Na[Au(CN)2] not Na[Au(CN)4], so I will leave the rest up to you.
Have a good day.
Explanation:
https://pubchem.ncbi.nlm.nih.gov/compound/5460536
that is the website i found that off of
https://www.webqc.org/molecular-weight-of-Na%5BAu%28CN%294%5D.html
this one tells you the element names.