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salantis [7]

Y = t*e^(-t/2)

y' = t' [e^(-t/2)] + t [e^(-t/2)]' = e^(-t/2) + t[e^(-t/2)][-1/2]=

y' = [e^(-t/2)] [1 - t/2] = (1/2)[e^(-t/2)] [2 - t] = - (1/2) [e^-t/2)] [t -2]

5 0

2 years ago

Read 2 more answers

If n2 = 1/16, then n could be which of the following?<br> -8<br> -1/4<br> 1/4

andreyandreev [35.5K]

$n^2=\dfrac{1}{16}\\\\n=-\dfrac{1}{4} \vee n=\dfrac{1}{4}$

6 0

2 years ago

The slope of a line is 1, and the y-intercept is -1. What is the equation of the line written in slope-intercept form?

scoray [572]

The slope-intercept form: y = mx + b

m - slope

b - y-intercept

We have: m = 1 and b = -1. Substitute:

y = 1x - 1

<h3>Answer: y = x - 1</h3>

7 0

3 years ago

Corinne bought 5 bags of chips and 4 jars of dipping sauce for $21.82. At the same prices, Ginger bought 4 bags of chips and 3 j

Harman [31]

Answer:

$4.96

Step-by-step explanation:

3 0

2 years ago

The price of a coat increased from $78 to $92. What is the price increase percentage?

blagie [28]

Answer:

18%

Step-by-step explanation:

Since the original price is $78 then this is the original 100% of the price. The new price will be marked up x percent and be $92. To find the new price set up a proportion with these values:

$\frac{92}{78}=\frac{x}{100}$

Solve for the original price by cross multiplying numerator with denominator.

x(78) = 92(100)

78x = 9200

x= 117.9 = 118%

This is 18% more or over the original price.

5 0

2 years ago