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GrogVix [38]
2 years ago
8

Find the 120th term, given the first term and the common difference. a =52 and d=12  1

Mathematics
1 answer:
Sliva [168]2 years ago
6 0
The first term is 52, the second term is 52+(1*12), the third term is 52+(2*12), the fourth term is 52+(3*12)... the 120th term is 52+((120-1)*12)
Therefore the 120 term is: 1480
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Q6. (15 points) IQ examination scores of 500 members of a club are normally distributed with mean of 165 and SD of 15.
melamori03 [73]

Answer:

a) 0.8413

b) 421

c) P_{95} = 189.675

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 165

Standard Deviation, σ = 15

We are given that the distribution of  IQ examination scores is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

a) P(IQ scores at most 180)

P(x < 180)

P( x < 180) = P( z < \displaystyle\frac{180 - 165}{15}) = P(z < 1)

Calculation the value from standard normal z table, we have,  

P(x < 180) = 0.8413 = 84.13\%

b) Number of the members of the club have IQ scores at most 180

n = 500

\text{Members} = n\times \text{P(IQ scores at most 180)}\\= 500\times 0.8413\\=420.65 \approc 421

c) P(X< x) = 0.95

We have to find the value of x such that the probability is 0.95

P( X < x) = P( z < \displaystyle\frac{x - 165}{15})=0.95  

Calculation the value from standard normal z table, we have,  

P(z < 1.645) = 0.95

\displaystyle\frac{x - 165}{15} = 1.645\\\\x = 189.675  

P_{95} = 189.675

8 0
3 years ago
Which layer of the atmosphere reflects radio waves back to Earth? Mesosphere Stratosphere Thermosphere Troposphere BRAINLEST
nataly862011 [7]

Answer:

ionosphere

Step-by-step explanation:

In radio communication, skywave or skip refers to the propagation of radio waves reflected or refracted back toward Earth from the ionosphere, an electrically charged layer of the upper atmosphere

6 0
3 years ago
Read 2 more answers
The least of 3 consecutive integers is a, and the greatest is z. What is the value of a + 2z/ 2 in terms of a?
jasenka [17]

Answer:

The value of a + 2z/ 2 in terms of a is (3a+4)/2

Step-by-step explanation:

least of 3 consecutive integers is a, and the greatest is z

if a is the least one

we know that integers differ by value of 1.

example -2, -1, 0, 1,2

they all differ by

then next consecutive integer will be a+1

third integer will be  second integer +1 = a+1 + 1 = a+2

Thus, 3 consecutive integer

a , a+1, a+2

but given that greatest is z

thus, a+2 is greatest and hence

a+2 = z

we have to find   value of a + 2z/ 2 in terms of a

a + 2z/ 2 = a + 2(a+2)/2 = (a+ 2a +4)/2 = (3a+4)/2.

The value of a + 2z/ 2 in terms of a is (3a+4)/2

4 0
3 years ago
What is the simplified form of 3.1 - 5.8n - 4n + 8?
lana66690 [7]

Answer:

-9.8n + 11.1

Step-by-step explanation:

1. Combine like terms

      -5.8n - 4n = -9.8n

      3.1 + 8 = 11.1

2. -9.8n +11.1

8 0
3 years ago
Read 2 more answers
What is ∛1728. Then multiplied by ∛14903
NeTakaya

Cube root of 1728 is 12 and on multiplying it by cube root of 14903 we get 295.306.

<u>Solution: </u>

Need to calculate \sqrt[3]{1728} and then multiply the result by \sqrt[3]{14903}

Let us first evaluate \sqrt[3]{1728}

\Rightarrow \sqrt[3]{1728}=\sqrt[3]{12 \times 12 \times 12}=12

As need to multiply 12 by \sqrt[3]{14903}

\Rightarrow 12 \times \sqrt[3]{14903}

On solving \sqrt[3]{14903}, we get

\sqrt[3]{14903}=24.608

\Rightarrow 12 \times \sqrt[3]{14903}=12 \times 24.608=295.306

Hence cube root of 1728 is 12 and on multiplying it by cube root of 14903 we get 295.306.

8 0
2 years ago
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