We are given that:
p is greater than 25, this means that p>25
p ∈ ]25,∞[ ...........> interval I
q is less than 35, this means that q<35
q ∈ ]-∞,35[ ...........> interval II
The given condition <span>p ∧ q is true means that (p and q) is true. In other word, their intersection is true.
Therefore, the final result would be the intersection between the two intervals (interval I and interval II)
Bases on the above, the final answer would be:
</span>]-∞,35[ ∧ ]25,∞[ which is ]25,35[<span>
</span>
= m^4 + 28m^2 - 36m^4 + 8m^5
= 8m^5 - 35m^4 + 28m^2
Answer
polynomial in standard form
8m^5 - 35m^4 + 28m^2
The weight of the pipe is 2287.4gm.
<h3>What is Unit of Measurement?</h3>
It is definite magnitude of a quantity, defined and adopted by convention or by law, that is used as a standard for measurement of the same kind of quantity.
It is given,
A metal pipe is 1.4 m long
Length of metal pipe is 1.4m=1400mm
Its internal diameter is 25 mm
Radius =12.5mm
Thickness=1mm
outer radius=12.5+1=13.5mm
volume of pipe=
V=π(R²−r² )h
V=3.142(13.5²-12.5²)1400
V=3.142(182.25-156.25)1400
V=3.142(26)1400
V=114368.8
1 mm³ of the metal weighs 0.02 gm
So 1.4 m long metal weights 114368.8×0.02=2287.4gm
Hence, the weight of the pipe is 2287.4gm.
To learn more on Unit of Measurement click:
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Answer:
5 cm approx
Step-by-step explanation:
Given data
Diameter= 20cm
radius= 10cm
Volume= 1570cm^3
We know that the expression for the volume of the container/cylinder is
V= πr^2h
1570= 3.142*10^2*h
1570=3.142*100*h
1570=314.2h
h= 1570/314.2
h=4.99 cm
Hence the height is 5 cm approx
