3 years ago

Find the slope of the tangent line to the parabola y=4x-x^2 at the point (1,3)

1 answer:

7 0

Y=4x - x²
dy/dx = 4-2x
dy/dx | x=1 : 4-2(1) = 4-2= 2
gradient= 2

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anastassius [24]

Answer:

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Alright, so by using the "keep me, change me, turn me over" method - we can easily solve this:

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I hope I was of assistance! #SpreadTheLove <3

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