Find the slope of the tangent line to the parabola y=4x-x^2 at the point (1,3)
1 answer:
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Answer:
(1)The value of x is -9 .
Option (B) is correct .
(2)The value of x is 13 .
Option (A) is correct .
(3)The value of the x is 11 .
Option (D) is correct .
(4) The value of the x is -15 .
Option (A) is correct .
(5)The value of the x is -11 .
Option (C) is correct .
Step-by-step explanation:
First Part
As given
4x = -36
x = -9
Therefore the value of x is -9 .
Option (B) is correct .
Second Part
As given
5x - 15 = 50
5x = 50 + 15gg
5x = 65
x = 13
Therefore the value of x is 13 .
Option (A) is correct .
As given
4(x+2)-17=35
4x + 8 - 17 = 35
4x = 35 + 17 - 8
4x = 44
x = 11
Therefore the value of the x is 11 .
Option (D) is correct .
Fourth Part
As given
6x+12=4x-18
6x-4x = -12-18
2x = -30
x = -15
Therefore the value of the x is -15 .
Option (A) is correct .
Fifth Part
As given
Simplify the above
4x-10+5×2 = 2x-22
4x-10+10= 2x-22
4x-2x = -22
2x=-22
x = -11
Therefore the value of the x is -11 .
Option (C) is correct .