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LuckyWell [14K]
3 years ago
11

Find the slope of the tangent line to the parabola y=4x-x^2 at the point (1,3)

Mathematics
1 answer:
Anna35 [415]3 years ago
7 0
Y=4x - x²
dy/dx = 4-2x
dy/dx | x=1 : 4-2(1) = 4-2= 2
gradient= 2
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Y+5=9/2(x+7) in standard form
ZanzabumX [31]

Answer:

2x-y=-1

Step-by-step explanation:

y + 9 = 2(x + 5)

y + 9 = 2x + 10 [distribute]

y = 2x + 1 [subtract 9 from both sides]

y - 2x = 1 [subtract 2x from both sides]

-2x + y = 1 [put x first]

2x - y = -1 [multiply by -1 to make x coefficient positive]

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GuDViN [60]

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To get a 15 in the denominator of 1/3, we multiply the numerator and the denominator by 5 which gives us 5/15.

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3 years ago
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