Please help me on this question
1 answer:
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Answer:
Step-by-step explanation:
observe
||a–b+c|| = ||a+b+c||
(a-b+c)² = (a+b+c)²
(a+b+c)² – (a-b+c)² = 0
((a+b+c)+(a-b+c))((a+b+c)–(a-b+c)) = 0
(2a+2c)(2b) = 0
(a+c)b = 0
a•b + c•b = 0
||a||×||b||×cos(π/8) + ||c||×||b||×cos(θ) = 0
Answer:
Step-by-step explanation:
You are going to integrate the following function:
(1)
furthermore, you know that:
lets call to this integral, the integral Io.
for a general form of I you have In:
furthermore you use the fact that:
by using this last expression in an iterative way you obtain the following:
(2)
with n=2s a even number
for s=1 you have n=2, that is, the function g(x). By using the equation (2) (with a = 1) you finally obtain: