Answer:
Yes. The two elements can combine to form different compounds.
Explanation:
Two elements can combine at different ratios.
Consider CO and CO₂. Both are made from carbon and oxygen. However, C and O combine at a 1:1 ratio in CO but at a 1:2 ratio in CO₂. CO is a fuel; it burns in the air. CO₂ does not burn in the air; it is used to put out fires and is found in extinguishers. CO and CO₂ are two distinct compounds.
There are many ways for the elements to combine with each other. As a result, the first twenty elements on the periodic table alone can produce a large number of compounds.
Answer:
it is Calcium (Ca)
4th period, 2nd group, 2 valence electrons
The answer for the following problem is mentioned below.
- <u><em>Therefore the final moles of the gas is 14.2 × </em></u>
<u><em> moles.</em></u>
Explanation:
Given:
Initial volume (
) = 230 ml
Final volume (
) = 860 ml
Initial moles (
) = 3.8 ×
moles
To find:
Final moles (
)
We know;
According to the ideal gas equation;
P × V = n × R × T
where;
P represents the pressure of the gas
V represents the volume of the gas
n represents the no of the moles of the gas
R represents the universal gas constant
T represents the temperature of the gas
So;
V ∝ n
= ![\frac{n_{1} }{n_{2} }](https://tex.z-dn.net/?f=%5Cfrac%7Bn_%7B1%7D%20%7D%7Bn_%7B2%7D%20%7D)
where,
(
) represents the initial volume of the gas
(
) represents the final volume of the gas
(
) represents the initial moles of the gas
(
) represents the final moles of the gas
Substituting the above values;
= ![\frac{3.8 * 10^-4}{n_{2} }](https://tex.z-dn.net/?f=%5Cfrac%7B3.8%20%2A%2010%5E-4%7D%7Bn_%7B2%7D%20%7D)
= 14.2 ×
moles
<u><em>Therefore the final moles of the gas is 14.2 × </em></u>
<u><em> moles.</em></u>
Answer:
B) 2Crº + 6e- --> 2Cr3+
Explanation:
The process of oxidation is where electrons are lost. Thus, out of the 2 ions that change charge(Cr and Cu), we must choose the one where the oxidation number increases(which means electrons are lost). Cr goes from an oxidation number of 0 to an oxidation number of 3+, while Cu goes from an oxidation number of 2+ to 0. Thus, we are looking at the half reaction for Cr. Half reactions never have subtracting electrons, so the answer must be B. I am assuming that last plus should be a -->