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serg [7]
3 years ago
8

Imagine that you're writing a paper on the topic of ocean acidification. Find two articles about ocean acidification on the Inte

rnet that you could use in your research. Name them Source 1 and Source 2, and include a link to each source. Be sure to also include the name of the website or organization that published the source.
Chemistry
1 answer:
pishuonlain [190]3 years ago
4 0

Answer:

See explanation

Explanation:

When you are writing a scholarly paper, you have to conduct a thorough search for source materials online. These sources must be reliable, credible and contain verifiable information. In a project such as writing a paper on the topic 'ocean acidification', the following materials are relevant;

Source 1) 'Functional impacts of ocean acidification in an ecologically critical foundation species,'; Brian Gaylord, Tessa M. Hill, Eric Sanford, Elizabeth A. Lenz, Lisa A. Jacobs, Kirk N. Sato, Ann D. Russell, Annaliese Hettinger; Journal of Experimental Biology 2011 214: 2586-2594; doi: 10.1242/jeb.055939

Source 2) 'Impacts of ocean acidification on marine fauna and ecosystem processes'; Fabry, V. J., Seibel, B. A., Feely, R. A., and Orr, J. C. ; ICES Journal of Marine Science, 65: 414–432; doi: 10.1093/icesjms/fsn048

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How many moles of calcium atoms are in 77.4g of Ca?
lina2011 [118]

Answer:

1.93 mol Ca

Explanation:

Use Calcium's molar mass to convert g of Ca into mol of Ca.

6 0
3 years ago
A student carries out this chemical reaction in a beaker:
nydimaria [60]

Answer:The correct answer is option (C).

Explanation:

Zn+CuCl_2\rightarrow Cu+ZnCl_2

After the reaction between Zinc and copper(II) chloride, Zinc chloride and copper will be obtained as a product. This reaction occurs because zinc is more reactive than copper which displaces the copper from its aqueous solution.

The student will expect to find copper metal at bottom of the beaker with aqueous solution of zinc chloride.

Hence the correct answer is option (C).

7 0
3 years ago
A balloon contains 0.140 molmol of gas and has a volume of 2.78 LL . If an additional 0.152 molmol of gas is added to the balloo
levacccp [35]

Answer:

The final volume will be 5.80 L

Explanation:

Step 1: Data given

Number of moles gas = 0.140 moles

Volume of gas = 2.78 L

Number of moles added = 0.152 moles

Step 2: Calculate the final volume

V1/n1 = V2/n2

⇒ with V1 = the initial volume = 2.78 L

⇒ with n1 = the initial number of moles = 0.140 moles

⇒ with  V2 = The new volume = TO BE DETERMINED

⇒ with n2 = the new number of moles = 0.140 + 0.152 = 0.292 moles

2.78/0.140 = V2 /0.292

V2 = 5.80 L

The final volume will be 5.80 L

8 0
3 years ago
"A base is a substance that produce OH-ions." Which definition of a base is this?
Andru [333]

Answer:

C. Arrhenius

An Arrhenius base is a substance that dissociates in water to form hydroxide (OH–) ions. In other words, a base increases the concentration of OH– ions in an aqueous solution.

Explanation:

pls mark as brainliest

3 0
3 years ago
A solution of malonic acid, H2C3H2O4 , was standardized by titration with 0.1000 M NaOH solution. If 21.17 mL of the NaOH soluti
MrRa [10]

Answer: The molarity of the malonic acid solution is 0.08335 M

Explanation:

H_2C_3H_2O_4 +2NaOH\rightarrow Na_2C_3H_2O_4+2H_2O

To calculate the molarity of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is H_2C_3H_2O_4

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is NaOH.

We are given:

n_1=2\\M_1=?\\V_1=12.70mL\\n_2=1\\M_2=0.1000M\\V_2=21.17mL

Putting values in above equation, we get:

2\times M_1\times 12.70=1\times 0.1000\times 21.17\\\\M_1=0.08335M

Thus the molarity of the malonic acid solution is 0.08335 M

5 0
3 years ago
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